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grep command

 
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# 1  
Old 04-25-2008
grep command
how can i grep number in a file

if i want to grep 1234
can i use?

read inp1 inp2
echo inp1 > inp1.txt ;echo inp2 > inp2.txt
if inp=`grep -w [0-9] inp1.txt` -o inp1=`grep -w [0-9] inp2.txt`


thanks
# 2  
Old 04-25-2008
You can directly grep the number.
Code:
grep -w 1234 filename

If you want to grep any 4 digit number, you can use
Code:
grep -w [0-9][0-9][0-9][0-9] filename

# 3  
Old 04-25-2008
grep command
i know what you mean
but the problem is i do not know what the user will input
the user may input anything and i need to check if the input is number . else the error should be display
# 4  
Old 04-25-2008
Numeric Check
As I know, there is no straight forward numeric check in shell script.
Through logic you can do.
--
typeset -i num
echo "Please enter string :"
read str
num=`expr $str + 1 2>/dev/null`
if [ $? -eq 0 ]
then
echo "Entered string is a number $str"
else
echo "Entered string is not a number $str"
fi
--
Hope it will help
Thanks
Sumit
# 5  
Old 04-29-2008
grep command
hi,

is there any simpler code using grep command to test whether input is number or not?

thanks
# 6  
Old 04-29-2008
Be sure to add an extra check whether the user has given 0 as input when using sumitc's suggestion, which is the far better way to accomplish what you really want.

Generally one could render your idea in a more elegant way as follows
Code:
read value
value=`echo $value|grep -w [0-9]`

# 7  
Old 05-01-2008
grep command
hi,
that does work but it doesnot support input more than one digit
if i want to enter number with 2 digits, the command does not work,
what should i alter to allow the code to read input of more than one digit?
thanks
 
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