UNIX for Dummies Questions & Answers

Hello,

I have a file where I need to search for a word in a line and then break the line into two lines.

I have the following file and I want the below result

File1:
PROJ=Workflow System CPPDOC=QUOTE
PROJ=center Workflow System CPPDOC=CONTRACT
PROJ=Workflow System CPPDOC=CPP CENTER
PROJ=center Workflow System CPPDOC=CPP TEAM
PROJ=CP flow System CPPDOC=TEST PLAN

Result:
PROJ=Workflow System
CPPDOC=QUOTE
PROJ=center Workflow System
CPPDOC=CONTRACT
PROJ=Workflow System
CPPDOC=CPP CENTER
PROJ=center Workflow System
CPPDOC=CPP TEAM
PROJ=CP flow System
CPPDOC=TEST PLAN

I started by trying to print the first part of the line up to CPPDOC for each line.

sed -n '/PROJ/,/CPPDOC/p' File1

but its just dumping the contents of File1

can someone explain why sed is not picking up the text with between the regular expresions?

Also, can someone shed light on another way to get the resulting file?


thanks

I'd use something like

Code:

sed 's/CPPDOC=/\nCPPDOC=/' < File1

Code:

sed 's/CPPDOC/\
CPPDOC/' file

thanks to shamrock and smiling dragon...it works perfect

I'm just curious but can you explain why the command I issue dumps the whole file?

sed -n '/PROJ/,/CPPDOC/p' File1


I thought it would read everyline and print all text in between those words for each line that it finds the start and stop parameters.



thanks

the -n option that you are using supresses automatic display of input lines
edit: by default, sed writes each input line to output after processing it. this option prevents that

what you need is the s (substitute) command to replace the space in between the two words with a newline character