I also need some quoting help. I tracked my problem down in a simple example.
I have a grep that is working if typed at the shell prompt (it is important for me to have a space in the character class):
But included in a script file (lets say file 'runMe') like the following:
Executing the file 'runMe', I get the following error: grep: RE error in '[a-zA-Z [ ] imbalance or syntax error
I googled/searched here for the error and for quoting or inserting something else which recognizes a space character, but with no success yet.
Also I tried various quotings in runMe, like "'[a-zA-Z ]{30}:'" or "\"[a-zA-Z ]{30}:\"" or quoting the space character like "[a-zA-Z ]{30}:" but all lead to the same error message. Seems like it is breaking at the space?
Curious for me:
If I execute the script and copy the line which is printed by the 'echo' statement and paste this line at the command prompt, that works! It just doesn't work within the script...
Maybe this not the adequate topic, because its more a grep issue than a quoting issue. If so, please be patient with me
FYI:
I'm relatively new to unix.
In 'myFile', I want to (simplified for this issue) match lines, that have the first 30 characters being (a letter or a space), followed by a colon.
I've aliased grep to /usr/xpg4/bin/grep (and also tried /usr/xpg4/bin/grep manually without alias).
thanks in advance for any hints, Thinkpositiv
Last edited by Thinkpositiv; 04-29-2008 at 11:32 AM..
I'm back with a similar issue
Basically I'm grep'ing a file for a pattern. The pattern contains " (double quotes) and a space. So I escaped the quotes. But how do I use this variable in the grep call?
Neither (a) nor (b) works. From my understanding I'd have to use (a), but searchString should contain path=\"asdf\", so I need to declare it like this?
Still no results, the variable found is always empty, although the searchString manually pasted into the grep call works.
Has anyone an idea/hint for me?
Thanks, regards, Thinkpositiv
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