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# 1  
Old 10-04-2007
grep question
I wanted to search a for all lines containing ERROR but not errors that contained the word "foo" (for example). The only way I could figure out to do it was:

grep ERROR myfile.log | grep -v foo

is there a way to do this with one grep command instead of two? One grep is faster than two, especially for large files like log files.Smilie
# 2  
Old 10-04-2007
Use:

Code:
awk '/ERROR/&&!/foo/' file

or:

Code:
fgrep ERROR file|fgrep -v foo

# 3  
Old 10-05-2007
Sanju
Hi use
grep -r "ERROR" *
# 4  
Old 10-05-2007
radoulov, isn't "fgrep ERROR file|fgrep -v foo "-the same as doing "grep ERROR file | grep -v foo", except it uses fgrep instead of grep? Is there some advantage for fgrep in this case?

The awk thing is pretty cool - I tried it and it works great. I'll have to look into awk more - I know nothing about it (yet!).

sanjustudy, I don't understand how grep -r "ERROR" * will do what I want. I thought "-r" was for searching directories recursively. Also, I don't see how it searches for "foo".
# 5  
Old 10-05-2007
Quote:
Originally Posted by tim-bobby
radoulov, isn't "fgrep ERROR file|fgrep -v foo "-the same as doing "grep ERROR file | grep -v foo", except it uses fgrep instead of grep? Is there some advantage for fgrep in this case?
[...]
If you don't search for a RE, it should be faster:

Quote:
DESCRIPTION
The fgrep (fast grep) utility searches files for a character
string and prints all lines that contain that string. fgrep
is different from grep(1) and egrep(1) because it searches
for a string, instead of searching for a pattern that
matches an expression. It uses a fast and compact algorithm.
 
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