How to List and copy the files containing a string


 
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# 1  
How to List and copy the files containing a string

Smilie
I have more than 8000 files in a dir, I need to copy to other dir which containing the "sample"

I tried
grep -il "1189609240791-1268115603299237276@216.109.111.119 ' | cp /tmp/inv

Nothing is happening for long time for 100 file dir too,

Any one can help me?
# 2  
For filenames with no embedded spaces(or other pathological characters):

Code:
mv $(grep -l '1189609240791-1268115603299237276@216.109.111.119')  /tmp/inv

Otherwise write a loop.

Aah, and if you get "too many arguments",
use zsh/zargs Smilie

Last edited by radoulov; 09-28-2007 at 12:26 PM..
# 3  
Quote:
Originally Posted by radoulov
For filenames with no embedded spaces(or other pathological characters):

Code:
mv $(grep -l "1189609240791-1268115603299237276@216.109.111.119 ')  /tmp/inv

Otherwise write a loop.

Aah, and if you get "too many arguments",
use zsh/zargs Smilie
Its not working...Smilie

ctlrws001[/tmp/inv1]$ cp $(grep -l "1190151616066-4284832706333417688@216.109.111.119') /tmp/inv/test
>
ctlrws001[/tmp/inv1]$ grep -l "1190151616066-4284832706333417688@216.109.111.119
>
# 4  
The quotes are mismatched.
# 5  
Quote:
Originally Posted by reborg
The quotes are mismatched.
Yep, corrected Smilie
# 6  
Quote:
Originally Posted by redlotus72
Its not working...Smilie

ctlrws001[/tmp/inv1]$ cp $(grep -l "1190151616066-4284832706333417688@216.109.111.119') /tmp/inv/test
>
ctlrws001[/tmp/inv1]$ grep -l "1190151616066-4284832706333417688@216.109.111.119
>
Check the corrected version Smilie
# 7  
Just curious, I tried this:
Code:
zsh 4.3.4% for i ({1..400000}) touch "$i".txt

Ctrl+C after a while.
Code:
zsh 4.3.4% rm *txt
zsh: argument list too long: rm
zsh 4.3.4% autoload zargs
zsh 4.3.4% zargs *txt rm --
zargs:168: subscript too big: 397905
zsh 4.3.4% while :;do rm *.txt([1,20000]);done
zsh: argument list too long: rm

The solution was:
Code:
while :;do rm *.txt([1,10000]);done

 

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