File/directory information......

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# 29  
Old 01-08-2002
Jimbo its definatly something to do with the sed command
sed "s/./& /g"

Says its not recongnised, tr command is workin fine now.

Ne1 know of ne alternatives for converting
e.g. 421000000 to 4 2 1 0 0 0 0 0 0 (need conversion to add spaces)??????

# 30  
Old 01-08-2002
What is the output of the following:

uname -a
echo $PATH

Also, do:

find / -type f -name sed 2> /dev/null

If the find command finds a sed, such as /usr/bin/sed, then reference that instead of the unqualified "sed".
# 31  
Old 01-08-2002
I think the best approach is to break the permission string up into an array with each element of the array being a single character. Then a few "if" statements can handle those pesky suid, sgid and sticky bits. Once they are gone, what's left is really a binary number with hyphen being a zero and everything else being a one. We can then convert that binary number to octal. Finally we just add in any of those high bits we found.

Part of the problem may be that the OP has a PATH with some screwy versions of normal system commands. So setting the PATH is probably wise.

Here is a script that displays the numeric mode for a file that is passed as a argument...
#! /usr/bin/ksh

integer -i8 octal

ls -l $1 | read permstring junk
set -A perms -- $(print -- ${permstring#?} | sed 's/./& /g')

[[ ${perms[2]} = S ]] && { ((extras=extras+4000)); perms[2]=- ; }
[[ ${perms[2]} = s ]] && { ((extras=extras+4000)); perms[2]=x ; }
[[ ${perms[5]} = S ]] && { ((extras=extras+2000)); perms[4]=- ; }
[[ ${perms[5]} = s ]] && { ((extras=extras+2000)); perms[4]=x ; }
[[ ${perms[8]} = T ]] && { ((extras=extras+1000)); perms[8]=- ; }
[[ ${perms[8]} = t ]] && { ((extras=extras+1000)); perms[8]=x ; }

binary=2#$(print -- ${perms[@]} | sed 's/ //g;s/-/0/g;s/[^0]/1/g')
result=$(echo $octal)

echo $result

exit 0

Makaveli.2003, does this script work for you? And I too would like to know what "uname -a" and "echo $PATH" give you.
# 32  
Old 01-08-2002
uname -a
SunOS babbage 5.6

echo $PATH

find / -type f -name sed 2> /dev/null
# 33  
Old 01-08-2002
I'm sure there's an easier or MUCH cleaner way... but this will give you numeric permissions on a filename:

NUMPERM=`ls -l $name |awk '{print $1}' |sed 's/-rwx/7/g; s/rwx/7/g; s/rw-/6/g; s/r--/4/g; s/r-x/5/g; s/d//g; s/^-//g'`

You could pipe this to the cut command for user/group/all individual permissions, ie.....

USER=`$NUMPERM |cut -c1`
GOURP=`$NUMPERM |cut -c2`
ALL=`$NUMPERM |cut -c3`

Hope this helps.
# 34  
Old 01-08-2002
davidl tried wat u said, but didn't seem to work, don't know why.

Your idea seems a bit complex compared with Jimbo's, its definatly something to do with the sed command
sed "s/./& /g"
Smilie Smilie
# 35  
Old 01-09-2002
Hmm, maybe you could try using the different "sed" binaries... each of:

They may each "behave" differently in how they interpret regular expressions...
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