UNIX for Dummies Questions & Answers

This is a long shot, but there are many bright folks on here

My next vi drama involves a using a prototype file for a makefile. I have an old prototype file but its not in correct format. It's formated as:

/the/old/path/file1 <garbage> <garbage>
/the/old/path/file2 <garbage> <garbage>
.
.

I'm trying to format it into:
f none /the/old/path/file1=../../the/old/path/file1 777 user group

I've made a copy of the old file, removed <garbage> and whitespaces, and got everything I need left of the "=". Now I'm looking for a quick way to get the right side of the "=" formated correctly.

Any help is appreciated

This would be easier with sed but I got this to work in vim and I think that it will work in plain old vi:

:%s+\(/.*\)=+\1=../..\1 777 user group+

It will certainly work in sed:

sed 's+\(/.*\)=+\1=../..\1 777 user group+' < inputfile > outputfile

It replied "Substitute pattern match failed."....but it's start...

I forgot to mention the all the files end with .src, but their names vary.

So for example....

65000.src
65010.src
.
.
.


Thanks.

edit: Gonna give sed a try.......fingers crossed

Thanks to one of my buddies, he was able to modify your original cmd and come up with:

sed 's+\(data.*\)+\1=../../\1 777 user group+' < inputfile > outfile

Many thanks!