UNIX for Dummies Questions & Answers

Hi,

when i am using lp command to print a report output in oracle apps, i am getting following error.

UX:lp: ERROR: Cannot access the file:
/var/spool/lp/temp/22571-1.
TO FIX: Make sure file names are valid.

Script

####BEGIN###################################################

date "+ %D %T Start : CHAR mode (DOS) printing"

request_id=`echo $1|cut -d' ' -f2|cut -d'=' -f2`; export request_id
file_name=`echo $1 | cut -d" " -f9 | sed 's/"//g'`; export file_name
printer=`echo $1 | cut -d" " -f10 | sed 's/"//g'`; export printer

echo "Check Printing...."
echo "File Name: " $file_name
echo "Printer: " $printer

touch /usr/tmp/t$request_id.txt

chmod 777 /usr/tmp/t$request_id.txt

lpstat -v $printer > /usr/tmp/t$request_id.txt

w_count=`cat /usr/tmp/t$request_id.txt |wc | awk '{print $3}'`

if [ $w_count -eq "0" ]
then
echo "Invalid Printer => " $printer
echo "Please give valid printer...."
exit 101
else
echo "UNIX Command to print"
echo "lp -d $printer $file_name"
lp -d $printer $filename
fi

rm /usr/tmp/t$request_id.txt
####END###################################################

any help will be appreciated.

Thanks in advance
rrs