UNIX for Dummies Questions & Answers

/home/documents/files/scooter17.dat

I am trying to cut out everything upto scooter17.dat so that it will only print out the scooter17.dat

any ideas?
great advices will be greatly appreciated.

Thank you


********Updated***************
Thank you for the replys. It works!! However, I am trying to do that for all the folders I have, meaning /home/documents/downloads/file1.dat and so on. So is there a way for me to write on script that only prints out the file name(file1.dat) for all the folders I have?

Thank you

what exactly are you trying?

$ ls lst where lst is the file you are working with
lst
$ cat lst
/export/home/prdcnlt2
$ cut -d/ -f4 lst
prdcnlt2

# basename /home/documents/files/scooter17.dat
scooter17.dat

Using built-ins:

Code:

file=/home/documents/files/scooter17.dat
echo ${file##*/}