UNIX for Dummies Questions & Answers

Hi,
I am trying to write a script to Count Files in a directory located on a remote server and send an email Notification if it exceeds a limit. The code given below doesnot check the condition and sends the mail everytime irrespective of the condition. I have put this script in the cron. Can anybody please point out the mistake I am making.

#!/bin/ksh
limit=50
file_length= rsh invuk "ssh poller "ls -ltr /var/spool/get | wc -l""
if [ $file_length -ge $limit ]; then
echo "Test mail." |mailx xyz@yahoo.com
fi

Thanks.

Have you tested the script? Does it run ok if you run it manually? Have you setup the rsh and ssh password less authentication for the appropriate users?

Yes it runs fine also the no of files returned is correct. Its just that the condition is not getting checked. Thanks

i doubt here,

where is the value that is returned is assigned to file_length,

something like,

Code:

file_length=`ssh abc_server /usr/bin/ls -l /tmp | /usr/bin/wc -l`

If I do echo $file_length I get the value.Correct me if I am not getting it...thanks

Try running the script with a 'set -x' in the line after the '#!'. The debug output should show you the value of the file_length variable and also the if condition as it is evaluated.
And please remove your mail id from the first post.

The issue seems to be with the value not getting populated in the file_length variable. The command gets run on the shell without the return value getting populated in the variable. How do I fix that. Thanks.