combine 2 lines (command & echo)

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# 8  
Old 10-05-2001
If you'd like, I can take it line by line... so you can see why it works the way it does... Just let me know.
# 9  
Old 10-05-2001
you'd do that?
thanks so much buddy!

you unix people are the best! Smilie
# 10  
Old 10-05-2001
Hey, no problem! I'll add lots and lots of comments, so you can "read along" with the code...

# The first thing I usually do in a script is define "functions"
# A function (like the one below) takes the form of
# function_name () {
# The Commands You Want Inside
# }
# Then you can just call the function_name to execute it!
# I like functions, even short ones like this, because
# it makes my "if" statements small and easy to read...
use_msg () {
echo "Usage:  `basename $0` [name]"
# Below is some very basic sanity checking.
# Basically, what it says, is "if there isn't exactly one argument,
# print the use_msg, then exit with errors"
# the "$#" operator counts the number of arguments. "-ne"
# Stands for "not equal".
if [ "$#" -ne "1" ] ; then
        exit 2
# Okay, so we made it this far, lets try to extract the real name
# from the passwd file. So we're searching passwd for a
# line beginning with (^) the user id (${1}). I put curly
# braces around some of my variables to help myself keep
# it seperate from the rest. You probably don't even really need
# it here. Also, make sure you are using backticks instead of
# single quotes! The backtick key is usually found near the top
# left of your keyboard, under the Esc key
name_t=`grep ^${1} /etc/passwd | cut -d: -f5 | cut -d, -f1`
#OK, if we can't extract the real name of the user, the variable
# $name_t will be empty. If that's the case, lets use the UserID
# instead. Otherwise, use the name. It'll make the script look
# nicer later on
if [ "$name_t" = "" ] ; then
# Here's your trick to see if the user exists:
who | grep $1 >/dev/null 2>&1
# Now watch what we're doing with the "logg" variable. If the
# user above command is successful ( exited with 0 status),
# then make the "logg" var empty. If the command did not 
# succeed (e.g. the user isn't logged in), then make logg equal
# to "not ". The space on the end is important, once again to
# make the output readable. Try it without the space, and
# see what happens.
if [ "$?" = "0" ] ; then
        logg="not "
# Alrighty! This is the fruits of your labor! You echo out the
# name, which we defined above (it'll either be the full name,
# or the usedid you gave it on the command line, remember?),
# then you'll see what happens with the logg var. Remember,
# since it's empty when the user is logged it, the string will say
# "is logged in". If the user is not logged in, it will insert
# "not", then a space to say "is not logged in". The curly braces
# are needed right here to keep $logg from looking like
# $logglogged, which the shell will not understand.
echo "${name} is ${logg}logged in"

Seriously though - the best experience is to run this script, then make some changes, to "get a feel" for how the different items interact. So experiment, play, improve, and have fun!

Please don't hesitate to post back with any other questions. It may make sense to me, but not to you. Or vice-versa.
# 11  
Old 10-05-2001

In answer to your original question, another way to do it is :

instead of:
grep $1 /etc/passwd | cut -f 5, -d : 
echo is logged on

echo `grep $1 /etc/passwd | cut -f 5, -d : ` is logged on

putting `` around a command means it will run first and be replaced by the output.
# 12  
Old 10-05-2001
tried that, didnt work Smilie i have tried that code before (found it on the net) i also tried piping it into echo, didnt work (hey im a rookie, im trying anything lol)

wow, thanks so much. ill read over your message and see if i can make heads or tails of the code. just scanning throught it, i noticed something.... why did you double cut?

name_t=`grep ^${1} /etc/passwd | cut -d: -f5 | cut -d, -f1`

oh and the 2>&1 is?

who | grep $1 >/dev/null 2>&1

thanks! im gonna read some more.
# 13  
Old 10-05-2001
it works!

hey everyone,
thanks for all your help. i got it working! Smilie
i installed UWIN on my system and run the program there, it worked. so i tried it on the AIX system, and it worked too!

this is what i used:

if [ $# != "1" ]
     echo "Usage: $0 [login name]"
     exit 2

who | grep $1 > /dev/null

if [ $? = "0" ]
   echo Yes `grep $1 /etc/passwd | cut -f5 -d:` is logged on
   exit 0
   echo No `grep $1 /etc/passwd | cut -f5 -d:` is not logged on
   exit 1

Livinfree, thanks for your script. i pretty much understood it all except for those 2 questions in the earlier post. ill work on adding the using UserID if user doesnt exist into my script. that was a good idea.

thanks once again!!
# 14  
Old 10-09-2001
Originally posted by primal
why did you double cut?

name_t=`grep ^${1} /etc/passwd | cut -d: -f5 | cut -d, -f1`

The reason I did that, was that some of the GECOS fields in my test passwd file are comma delimited. If the User's name is the only information that field is simply -
:Full Name:
In the case that It contains phone number, office number, so on, it looks like this -
:Full Name, Room Number, Work Phone, Home Phone:
I wanted to make sure that if more than one part of the field existed, we only grab the full name.

oh and the 2>&1 is?
who | grep $1 >/dev/null 2>&1

Oops, forgot to explain that. "2" is the file desciptor for "stderr", which is the standard error output. "1" is the descriptor for stdout, standard output. Some times you need to do something with both of them, to keep any output from showing up on your screen. What 2>&1 does, is sends stderr into stdout, so it will follow wherever you're sending the output, whether it's into /dev/null, or into a log file.

I may not be too helpful in explaining it here, but in this case, you probably don't really need it in this case. It's just one of those things I do out of habit...

thanks! im gonna read some more.

Hey, any time!
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