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Date format in Bash Script

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# 1  
Old 09-02-2013
Date format in Bash Script

Hi Experts,

We get "Day" of a month in a variable, so how to make date of out it?

To make more sense
if my variable $DAY contains "12" and month and year will be current date (as of today)
so I want to see as output as 2013-09-12.

How can I achive this bash script??

Any help is highly appreciated.

Thank you
# 2  
Old 09-02-2013
Simply, using:
# DAY=12
# date +%Y-%m-$DAY

There's no validation, though:
# DAY=31          
# date +%Y-%m-$DAY

This User Gave Thanks to Scott For This Post:
# 3  
Old 09-02-2013
$ day=02
$ date +%Y-%m-$day

# 4  
Old 09-02-2013
Thank youuuuuu

Thank you Scott
# 5  
Old 09-02-2013
Originally Posted by Scott
Simply, using:
# DAY=12
# date +%Y-%m-$DAY

Checking validity of scripts as root, there's confidence for ya Smilie
This User Gave Thanks to Skrynesaver For This Post:

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