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Bash - OR within an IF statement

 
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# 1  
Old 01-15-2013
Bash - OR within an IF statement
Hey guys,

Currently trying to write a wee script that runs only when logged in as one of two users. The rest of the script is working fine, but no matter what user I try to run it as, it always fails! This is the puzzling part:
Code:
if [[ $USER != "admin1"  ||  $USER != "admin2" ]]; then
        echo "Run script as admin "
        exit 1
else
        ... runs some script . . . 
fi

Does anyone have any ideas !? It's probably staring me straight in the face but as I'm still learning bash/scripting then it's going right past me!

Thanks guys for any help

Jim
# 2  
Old 01-15-2013
Your test can't be but true, use an AND, not an OR:

Code:
if [[ $USER != "admin1"  &&  $USER != "admin2" ]]; then
...

This User Gave Thanks to jlliagre For This Post:
jimbob01
# 3  
Old 01-15-2013
Code:
if [ "$USER" = "admin1" ] || [ "$USER" = "admin2" ]
then
        echo "Run scripts here"
else
        echo "Run script as admin "
        exit 1
fi

This User Gave Thanks to Yoda For This Post:
jimbob01
# 4  
Old 01-15-2013
Thanks guys! Brilliant - I've been tearing my hair out (well, whats left of it!) wondering how I couldn't get it to work, should have stopped by earlier.

You guys rock! Smilie
# 5  
Old 01-16-2013
bash also allows for a regex matching:
Code:
$ [[ "$USER" =~ admin[12] ]] && echo in || echo out
in

# 6  
Old 01-16-2013
Or ordinary pattern matching:
Code:
if [[ $USER != admin[12] ]]; then

or extended pattern matching:
Code:
shopt -s extglob
if [[ $U = !(admin1|admin2) ]]; then

Or you could use a case statement:
Code:
case $USER in 
  admin[12]) echo yes ;;
  *)         echo no ;;
esac

Code:
case $USER in 
  admin1|admin2) echo yes ;;
  *)             echo no ;;
esac

--
@RudiC: that would need to be ^admin[12]$
Last edited by Scrutinizer; 01-16-2013 at 08:10 AM..
This User Gave Thanks to Scrutinizer For This Post:
RudiC
# 7  
Old 01-16-2013
Absolutely right - thanks.
 
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