Remove the date portion from file name

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# 1  
Remove the date portion from file name

I am trying to remove the last field before the period (.) from a list of file names in a directory in a shell script.
Below is the list of file names.

PHP Code:
_ and the date part followed by it have to be removed and the result should be:
PHP Code:
I tried with cut. But as the date field position is dynamic, I could not get it through successfully. can some one help?

# 2  
perl -pe 's/_\d+//' file

# 3  
Hi bartus11, I am doing a unix script.. and I would like to do this in the script with shell commands..(bash) in my unix script.. My system is Linux.
# 4  
$ f=ENVID_Get_Source_Files_20120214092523.log
$ echo "${f%_*}.${f##*.}"

# 5  
Hi Scrutinizer, thanks for your quick response.. can you please explain me what is "${f%_*}.${f##*.}" ??
I am quite new in unix, please explain.
# 6  
Hi Vijay, this is called parameter expansion.
These 3 Users Gave Thanks to Scrutinizer For This Post:
# 7  
Scrutinizer, this was great. Thanks for the link, it is even useful to me in many cases.

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