One liner pattern search with awk/sed/grep


 
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# 1  
Old 01-31-2012
One liner pattern search with awk/sed/grep

I have an array containing bunch of characters. I have to check this array for specific character and if "Not Found than" use a goto statement to go to USAGE
Code:
set options = (A B C D E F)
@ i = 0
while ($i <= ${#options})
  if ($options[$i] != "F" || $options[$i] != "D") then
  goto USAGE
 endif
@ i++
end

In above code I am looking for F and D and if not found than script goes to USAGE defined somewhere in script. I know it can be done with awk/sed/grep as one liner which I think more efficient. I am new to this and want to move away from doing things in an ancient way. Please help.
Thanks in advance
# 2  
Old 01-31-2012
Code:
 
$ echo "A B C D E F" | nawk '!/D/ && !/F/ {print "USAGE :: "}'
$
$ echo "A B C E " | nawk '!/D/ && !/F/ {print "USAGE :: "}'
USAGE ::

 
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