One liner pattern search with awk/sed/grep Post: 302594495

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Top Forums UNIX for Dummies Questions & Answers One liner pattern search with awk/sed/grep Post 302594495 by dixits on Tuesday 31st of January 2012 12:18:26 PM

01-31-2012

Registered User

One liner pattern search with awk/sed/grep

I have an array containing bunch of characters. I have to check this array for specific character and if "Not Found than" use a goto statement to go to USAGE

Code:

set options = (A B C D E F)
@ i = 0
while ($i <= ${#options})
  if ($options[$i] != "F" || $options[$i] != "D") then
  goto USAGE
 endif
@ i++
end

In above code I am looking for F and D and if not found than script goes to USAGE defined somewhere in script. I know it can be done with awk/sed/grep as one liner which I think more efficient. I am new to this and want to move away from doing things in an ancient way. Please help.
Thanks in advance

dixits

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