UNIX for Dummies Questions & Answers

dear all,

i'm new to unix and i try to figure out the best case for making list of vertical text to become horizontal and skip the line 1 and 2.

example text :

Data DATE XXXXX
MAX
47
53
49
51
48
48
7
46
51
8
25

I want to grep or any other way to make it like this :

47 53 49 51 48 48 7 46 51 8 25

so i dont want the Data DATE XXXXX & MAX

can u tell me how to do it, what is the best process to do this?

Code:

$ sed '1,2d' infile | xargs

hi its works but after the vertical number there are other lines, how to skip the other lines.

example :

Data DATE XXXXX
MAX
47
53
49
51
48
48
7
46
51
8
25

abcdefgasdfghjklwertyuiop
abcdefgasdfghjklwertyuiop
abcdefgasdfghjklwertyuiop
abcdefgasdfghjklwertyuiop
abcdefgasdfghjklwertyuiop
abcdefgasdfghjklwertyuiop
abcdefgasdfghjklwertyuiop
abcdefgasdfghjklwertyuiop

how to exclude the abcdefgasdfghjklwertyuiop ?

Code:

$ awk '!/abcdefg/' infile | sed '1,2d' | xargs

$sed '/.*[^0-9].*/d' FILE_NAME | xargs

one more ..

Code:

$ grep -vi "^[a-z]" infile | xargs

is it possible to limit the result just until n lines?

example :

Data DATE XXXXX
MAX
47
53
49
51
48
48
7
46
51
8
25

abcdefgasdfghjklwertyuiop
abcdefga123ertyuiop
abcde456fghjklwertyuiop
abcd756756ghjklwertyuiop
abcdefg78978978tyuiop
abcdefgasdfghjklwertyuiop
abcdefgasdfg675645rtyuiop
a12312dfghjklwertyuiop

I want the result to be :

47 53 49 51 48 48 7 46 51 8 25

line 1 and 2 are gone and line 14 until n will not be appear in result

---------- Post updated at 05:03 PM ---------- Previous update was at 04:46 PM ----------

tested and this works fine, thanks