UNIX for Dummies Questions & Answers

Hi Unix experts,

Believe me, this forum has been really great help and I searched for many things that were already answered before open new post that were just new versions of old one, but with this one, I just can't simply move any forward.

This must be quite easy, but I cant find where I am losing my head.

Here is the thing, I need to pass a command an attribute with following format:

Code:

' "server/project" '

(spaces and quotes are mandatory)

So let's see tests I did:

1- I manually indicate values in the command. Works fine

Code:

$istoolDir/istool import -replace -ds ' "VLIRODSU/TestProject" '

2 - Try to create the value passed to ds option in a previous variable

Code:

opciones="' \"$estaMaq/$proyecto\" '"
echo $opciones
$istoolDir/istool import -replace -ds $opciones

Executing the script...
When I execute the script, I get correct value when executing echo, but when command is launched, I got an error as the option passed was illegal, seems single quotes are missing

3 - Try to escape quotes:

Code:

$istoolDir/istool import -replace -ds ' \"' $estaMaq/$proyecto '\" '

But again, script execution fails:
Now both singe and double quotes seem to be missing in the option value


As said, I tried to research the forum but could not resolve the problem

If you guys help me out, it would be very appreciated

Thanks very much in advanced

Try this:

Code:

opciones=' "server/project" '
"$istoolDir"/istool import -replace -ds "' $opciones '"

Note that the identifier opciones is passed to istool in double quotes.