UNIX for Dummies Questions & Answers

Hello, I have a block of code (XML) that I would like to grep for certain information. The basic format of the XML is the following repeated a few hundred times, each time with a unique ID:

<Identifier ID="A" NAME="John Doe" AGE="32 Years" FAMILY="4" SEX="MALE"></Identfier>

I would like to create a statement that grabs the ID, Name, and Age of the individual.

What I've done so far is grep the XML file with the following:
grep "ID=" file1.xml

but when I do so, I get the entire line. Is there a command I can use that would give me an output similar to the following?:

HTML Code:

A    John Doe    32 Years

Code:

sed 's/.*ID=\"\(.*\)\" NAME=\"\(.*\)\" AGE=\"\(.*\)\" FAMILY.*/\1 \2 \3/' infile

rdcwayx, thanks for the help. I tried running your command, but the whole entire block was returned and not the text found within the quotes.

there are some hide characters in your files.

upload some samples here

Sorry for not being through. Here is a sample block:

<Identifier ID="A" Guid="{8a79eb5-88f8-4a7b-4a1b-67ff369be696}" NAME="JOHN DOE" QUALIFIER="YES" DT="3010" LIMITATOR="" Description="" Deadband="" Key="2887" STATUS="0" DOAP="0" AGE="32 YEARS" SEX="MALE">
</Identifier>

Code:

sed 's/.*ID="\([^"]*\)".*NAME="\([^"]*\)".*AGE="\([^"]*\)".*/\1 \2 \3/' infile |grep -v "<\/Identifier>"

rdcwayx,
thanks for all your help. Your command worked like a charm!