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awk or grep for integer only

 
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# 1  
Old 08-31-2004
awk or grep for integer only
how do you print the lines that contain integers only, using grep or awk?

thanks ,
apalex

------------------
this file below:
qwerty
01234
asdfgh
01234
qwer12
asdf05

will be:
01234
01234
qwer12
asdf05
# 2  
Old 08-31-2004
you could use awk to get only those records that are integers only as you asked. However your example, you include records that are alphanumeric

awk ' /[[:digit:]]/ { print $0 } ' your_file
# 3  
Old 08-31-2004
you are right sorry about that.

how to awk, to print the lines with integers only, having random patterns.

from:

qwerty
12345
asdfg
56789
zxcvb
00001
58364
22222


will be:

12345
56789
00001
58364
22222
# 4  
Old 08-31-2004
can this be done using the same command above?

thanks.
apalex
# 5  
Old 08-31-2004
Try using grep...

grep -E '^[0-9]+$' file1
# 6  
Old 09-01-2004
Quote:
can this be done using the same command above?
Yes. You can use the Awk command above to produce a list of entries composed of only integers.

awk ' /[[:digit:]]/ { print $0 } ' your_file

from:

qwerty
12345
asdfg
56789
zxcvb
00001
58364
22222


will be:

12345
56789
00001
58364
22222
 
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