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# 1  
Old 09-15-2010
Question Awk question
Hi all,

I assume this question involves an answer with awk(?). I'm able to figure out how to extract a certain word if spaces are involved, but have been having difficulty figuring this scenario out:

Code:
VAR="dig +time=1 +tries=1 +short @10.10.10.10 any s.10.1.1.1.test.com.test.net"

May I ask how I would extract the 1st IP address (always after an @ sign, then before the following space--in this case: 10.10.10.10) to be assigned to $FIRSTIPADDR

Thank you so much,
cg
# 2  
Old 09-15-2010
Try
Code:
FIRSTIPADDR=$(echo $VAR | awk '{sub("@","",$5);print $5}')
echo $FIRSTIPADDR

This User Gave Thanks to bartus11 For This Post:
chatguy
# 3  
Old 09-15-2010
try:
Code:
FIRSTIPADDR=`echo $VAR | awk '{ print substr($5,2) }'`
echo $FIRSTIPADDR

Last edited by john1212; 09-16-2010 at 04:32 AM.. Reason: my mistake it'was substr($5,1) The first character of a string is character number one.
This User Gave Thanks to john1212 For This Post:
chatguy
# 4  
Old 09-15-2010
Code:
$ echo $VAR | sed "s/.*@\([0-9]*\.[0-9]*\.[0-9]*\.[0-9]*\\).*/\1/"
10.10.10.10

This User Gave Thanks to anbu23 For This Post:
chatguy
# 5  
Old 09-15-2010
Another variation:
Code:
FIRSTIPADDR=$(echo $VAR | awk -F'[ @]*' '{$0=$5}1')
echo $FIRSTIPADDR

or:
Code:
v=${VAR#*@}; FIRSTIPADDR=${v%% *}
echo $FIRSTIPADDR

Last edited by Scrutinizer; 09-15-2010 at 06:17 PM..
This User Gave Thanks to Scrutinizer For This Post:
chatguy
# 6  
Old 09-16-2010
Thanks everyone. Everyone definitely has been very helpful, and the multiple responses have been very good as these have taught me how to adapt to similar (but different) scenarios I've been wanting to also cover in this script.

Thanks again,
cg
 
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