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function not see variable in script

 
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# 8  
Old 09-10-2010
Hi.

No. I used ${1:-file1} just because I got too lazy typing the filename in every time I ran the script! It means, if no filename is given on the command line, use a file called file1 instead.

So, apart from the ${x} versus x thing, there was really nothing wrong with your script!
# 9  
Old 09-10-2010
Quote:
Originally Posted by ShinTec
O
Scottn does this line
Code:
done < ${1:-file1}

tell the script to look in the current directory or am i way off
This reads "if no argument($1 not set or null) is passed use file1 as the default". If file1 is not in the current working directory then it will fail unless you pass it.

---------- Post updated at 20:50 ---------- Previous update was at 20:46 ----------
Quote:
Originally Posted by scottn
So, apart from the ${x} versus x thing, there was really nothing wrong with your script!
actually there was a problem with the regex -- . was matching all characters. some how this was siliently fixed in your code Smilie
# 10  
Old 09-10-2010
Hi.

A minor note: for the type of character class that you wanted to use:
Quote:
Originally Posted by ShinTec
...echo ${1} | grep -E '[:digit:]+.[:digit:]+' ...
You need to use an extra set of brackets:
Code:
       Finally,  certain  named  classes  of  characters are predefined within
       bracket expressions, as follows.  Their names are self explanatory, and
       they   are   [:alnum:],  [:alpha:],  [:cntrl:],  [:digit:],  [:graph:],
       [:lower:], [:print:], [:punct:], [:space:], [:upper:], and  [:xdigit:].
       For  example,  [[:alnum:]]  means  [0-9A-Za-z],  except the latter form
       depends upon the C locale and the ASCII character encoding, whereas the
       former  is  independent  of  locale  and character set.  (Note that the
       brackets in these class names are part of the symbolic names, and  must
       be  included  in  addition  to  the  brackets  delimiting  the  bracket
       expression.)

-- excerpt from man grep, q.v.

cheers, drl
# 11  
Old 09-10-2010
Quote:
Originally Posted by frank_rizzo
This reads "if no argument($1 not set or null) is passed use file1 as the default". If file1 is not in the current working directory then it will fail unless you pass it.

---------- Post updated at 20:50 ---------- Previous update was at 20:46 ----------



actually there was a problem with the regex -- . was matching all characters. some how this was siliently fixed in your code Smilie
Oh yes, the regex... Smilie (not sure what you mean by silently)

But apart from that...
Last edited by Scott; 09-10-2010 at 10:58 PM..
 
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