return a specific row using awk


 
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return a specific row using awk

Hello, I am using awk to process a file, and need to return a row that meets specific criteria.

awk 'BEGIN{sets variables}
{processes file, updates variables}
END{need to print a row that meets the criteria in one of the variables}

I have tried code in the END block like {print NR==var} but can't get it to work. I only need to print the one row that matches the value in the variable.

thanks
# 2  
Quote:
Originally Posted by badPuppy
Hello, I am using awk to process a file, and need to return a row that meets specific criteria.

awk 'BEGIN{sets variables}
{processes file, updates variables}
END{need to print a row that meets the criteria in one of the variables}

I have tried code in the END block like {print NR==var} but can't get it to work. I only need to print the one row that matches the value in the variable.

thanks
Hello
"END{print NR==var}" is not going to work as the value of NR iterates in the main body before the END part while the END part executes in the end.
you can do like ,
awk 'BEGIN{sets variables}{processes file,updates variables}NR==var{print}' infile
Regards.
 

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