Line number of an occurrence using grep


 
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# 1  
Line number of an occurrence using grep

Hi All,
is there a way to extract the line number of an occurrence using grep?
I know that with the -n option it prints out the line number as well.
I would like to assign the line number to a variable.
Thanks,
Sarah
# 2  
Code:
grep -n 'pattern ' inputfile | read number_var junk
echo $number_var

One way of many. This assumes the pattern occurs only one time in inputfile
# 3  
Code:
file="..."
pattern="..."
a=`cat -n $file | grep $pattern | awk '{print $1}'`

You have in $a the list of line numbers that match the pattern
# 4  
var=`grep -n pattern inputfile | cut -d : -f 1`
# 5  
Code:
var=$(grep -n 'pattern' infile)
echo ${var%%:*}

Code:
var=$(awk '/pattern/{print NR}' infile)

Code:
var=$(sed -n '/pattern/=' infile)


Last edited by Scrutinizer; 11-23-2009 at 01:45 PM..
# 6  
thank you all, how do I access the first value of the variable in case of more than one occurrence?
I tried var[0]...but with no success

---------- Post updated at 05:37 AM ---------- Previous update was at 04:14 AM ----------

Actually I am interested only in the first.

Code:
grep -n 'pattern ' inputfile | read number_var junk
echo $number_var

doesn't work.
Other methods work but I don't know how to access the first value in the returned variable.

I solved with

Code:
ISTHERE=`grep -n total tmp.tmp3 | head -1 | cut -d : -f 1`

I'm smart too!
Smilie

Last edited by f_o_555; 11-24-2009 at 09:14 AM..
 

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