hello everyone, i'm taking a class on unix and linux, and have come across a problem that my teacher couldn't figure out either:
the testing file i'm using:
so here's some things i've tried:
so, why does grep behave like that?, i thought that the output would be:
instead it acts like it broke, and outputs the entire file, any help is much appreciated
ok, i see thanks very much for your answer, this helps me understand what is going on, is their any way to achieve the output i desired with just grep or would i have to pipe it into other functions to achieve the output i desire?
that works on the small scale like here, but the end goal has 11 lines in front of, and 17 lines behind, and i only know of 1 point between those lines that is unique, the rest is repeated multiple times in the file, which is why i was hoping to figure this out with grep
ahh, didn't know that(i was taught piping in from cat, thanks)
however with the first grep -v -A 1 'figure' test, the output is the same as the input, making the second grep act the same inversing just that line, and not the last two lines
output of grep -v -A 1 figure test:
and piped into the second grep:
which would be the same as doing grep -v 'figure' test
is their any type of file comparision function that i could output the result into comapre that with the original file, and only output the diffrences?
i have this line of code that looks for the same file if it is currently running and returns the count.
`ps -eaf -o args | grep -i sfs_pcard_load_file.ksh | grep -v grep | wc -l`
basically it is assigned to a variable
ISRUNNING=`ps -eaf -o args | grep -i sfs_pcard_load_file.ksh |... (6 Replies)
Hi,
I have a number of files containing the information below.
"""""
Fundallinfo
6.3950 14.9715 14.0482
"""""
I would like to grep for Fundallinfo and use it to read the next line? I ideally would like to read the three numbers that follow in the next line and... (2 Replies)
Hello.
I want to get all modules which are loaded and which name are exactly 2 characters long and not more than 2 characters and begin with "nv"
lsmod | (e)grep '^nv????????????
I want to get all modules which are loaded and which name begin with "nv" and are 2 to 7 characters long
... (1 Reply)
I have a directory I need to grep which consists of numbered sub directories. The sub directory names change daily. A file resides in this main directory that shows which sub directories are FULL backups or INCREMENTAL backups.
My goal is to grep the directory for the word "full" and then... (2 Replies)
Hi All,
Please i need to know the difference between grep, egrep & grep -i when used to serach through a file.
My platform is SunOS 5.9 & i'm using the korn shell.
Regards,
- divroro12 - (2 Replies)
Hi All, I need to grep few files which has words like the below in the file name , which i want to put it in a file and and grep for the files which contain these names and move it to a new directory ,
full file name -C20091210.1000-20091210.1100_SMGBSC3:1000... (2 Replies)
Hello,
I'm working on unix with grep (GNU grep) 2.5.1. I'm going through some of the newer regex syntax using Regular Expression Reference - Advanced Syntax a guide.
ls -aLl /bin | grep "\(x\)"
Which works, just highlights 'x' where ever, when ever.
I'm trying to to get (?:) to work but... (4 Replies)
Hello,
I looking to use grep to return a string with exactly n matches.
I'm building off this:
ls -aLl /bin | grep '^.\{9\}x' | tr -s ' '
-rwxr-xr-x 1 root root 632816 Nov 25 2008 vi
-rwxr-xr-x 1 root root 632816 Nov 25 2008 view
-rwxr-xr-x 1 root root 16008 May 25 2008... (7 Replies)
Hi Guys,
I need to set the value of $7 to zero in case $7 is NULL. I've tried the below command but doesn't work. Any ideas. thanks guys.
MEM=`ps v $PPID| grep -i db2 | grep -v grep| awk '{ if ( $7 ~ " " ) { print 0 } else { print $7}}' `
Harby. (4 Replies)