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printing only the middle word between two patterns


 
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# 1  
Old 09-08-2009
printing only the middle word between two patterns

How would I print the word "and" between the words "FOO" and BAR" using sed? My file has three words in it FOO and BAR. I only want the word "and".

Thanks every one.
# 2  
Old 09-08-2009
Code:
sed -e's/\<FOO\>.*\<\(.*\)\>.*\<BAR\>/\1/'

# 3  
Old 09-09-2009
Code:
 awk '{ print $2 }' <In File>

If your infile contains 3 coloumns, then it will print middile coloumn only.
# 4  
Old 09-09-2009
Thanks Scrutinizer, that worked great.

How would I modify this to print an IP address?
(FOO 10.192.12.102 BAR)

I thought it would work for anything in between two words but I see it only works for text. I tried

sed -e's/\<FOO\>.*\<\([.0-9]*\).*/\1/'

but it does not produce and results.

Thanks
# 5  
Old 09-09-2009
Try this:

Code:
sed -e's/\<FOO\>\W\+\<\(.*\)\>\W\+\<BAR\>/\1/'

# 6  
Old 09-09-2009
Thanks Deepaks. That worked. What exactly is the command saying?
# 7  
Old 09-09-2009
Since you asked..

s means search and replace, the forward slash starts the match.
- match FOO in word boundaries ( \< and \> ), followed by
- At least one character that is not alphanumeric or underscore ( \W\+ )
- Then look for any characters ( .* ) in word boundaries.
- Mark these characters by using \( and \) so that we can reproduce it later using \1
- Then this is followed by non alphanumeric or underscore characters, followed by
- BAR in word boundaries
- / marks the end of the match
- \1 reproduces the marked characters
- / marks the end of the search and replace

Last edited by Scrutinizer; 09-09-2009 at 07:23 PM..
 

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