UNIX for Dummies Questions & Answers

Code:

$ sort -k 12 numbers.txt|uniq -f 11 -c|awk -f " " '$1==1{print}'|cut -f 2-
awk: can't open

What's in red?

sorry actually i have given the -f option instead of -F option
the code is :
$ sort -k 12 numbers.txt|uniq -f 11 -c|awk -F " " '$1==1{print}'|cut -f 2- >new_file



and i gave a space in those double quoues
regards,
Sanjay

you don't have to specify the FS, as it's space OR tab by default - you can drop the '-F' specification.
Furthermore, I'm not sure if this is what the OP is looking for, because somehow you're checking to see if the first field is '1'. I'm not sure that's what the OP is after.
Let's see if the OP validates the code/results.
I get the following output with your code - not the leading spaces:

Code:

   1 1 1 1 1 1 1 2 1 2 1 1 1_2 2_1
   1 1 1 1 1 1 1 1 4 1 1 1 1_4 4_1

the first field is the frequency(due to uniq -c option) of the records which i serched for $1=1 and then used cut -f 2- which will exclude the first field( the frequecy field). The logic is that.

thanks and regards,
Sanjay

I also do not get the correct output with your code:

Code:

> sort -k 12 numbers.txt|uniq -f 11 -c|awk -F " " '$1==1{print}'|cut -f 2-
   1 1 1 1 1 1 1 1 4 1 1 1 1_4 4_1

I don't know about every version of 'cut' out there but mine has a default delimiter of <tab>. So, to make this work on my system, the 'cut' needs to specify the delimiter. And because it counts each delimiter character, and this line includes leading spaces, -f2- doesn't cut it either.

My perl solution didn't have this problem. To get this solution to work on my system, it has to be like this:

Code:

> sort -k 12 numbers.txt|uniq -f 11 -c|awk -F " " '$1==1{print}'|cut -f 5- -d " "
1 1 1 1 1 1 1 4 1 1 1 1_4 4_1

thanks to let me know regarding the output ,i ran again and also facing the same problem(not getting the correct out put).i am trying to correct the code.

thanks again to vgresh and vi_curious