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Extract Unique Values from file


 
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# 1  
Old 08-31-2009
Question Extract Unique Values from file

Hello all,

I have a file with following sample data

2009-08-26 05:32:01.65 spid5 Process ID 86:214 owns resources that are blocking processes on Scheduler 0.
2009-08-26 05:32:01.65 spid5 Process ID 86:214 owns resources that are blocking processes on Scheduler 0.
2009-08-26 05:32:01.65 spid5 Process ID 84:127 owns resources that are blocking processes on Scheduler 2.
2009-08-26 09:49:53.46 spid5 Process ID 86:214 owns resources that are blocking processes on Scheduler 0.
2009-08-26 15:51:28.51 spid5 Process ID 102:17 owns resources that are blocking processes on Scheduler 12.
2009-08-26 15:51:28.51 spid5 Process ID 102:17 owns resources that are blocking processes on Scheduler 12.
2009-08-26 15:51:28.51 spid5 Process ID 102:17 owns resources that are blocking processes on Scheduler 12.


I need to extract the unique Process IDs

So the output should be { though the order does not matter }

86
84
102

Its the unique values occuring between "Process ID" and the ":" on each line excluding the blank white space after ID . Process ID 102:

Any suggestions ?Smilie
# 2  
Old 08-31-2009
One of the possibilities:
Code:
sed -e's/^.*Process ID \([0-9]*\):.*$/\1/' samplefile |sort -nu

or, using cut
Code:
cut -c41- samplefile |cut -d: -f1|sort -nu


Last edited by Scrutinizer; 08-31-2009 at 08:17 PM..
# 3  
Old 08-31-2009
Another possible way,

Code:
perl -ne  'print "$1\n" if /Process ID (\d+):\d+ / && !$_[$1]++' file

# 4  
Old 09-01-2009
Thank you all Scrutiniser and Rubin for your wonderful responses. It is incredible what can be done with shell scripting though it is very crytic.

Just a quick one.

How to get the above ouput as a CSV comma seperated list ?

So it would be : 84,86,102
# 5  
Old 09-01-2009
Quote:
Originally Posted by simonsimon
...
How to get the above ouput as a CSV comma seperated list ?

So it would be : 84,86,102

Given your input, one way would be:

Code:
$ perl -ne  'print $s=$s?",".$1:$1 if /Process ID (\d+):\d+ / && !$_[$1]++; print "\n" if eof' file
86,84,102


Last edited by rubin; 09-01-2009 at 03:07 PM.. Reason: trimmed it a bit
# 6  
Old 09-01-2009
Or you can append
Code:
|xargs|tr " " ","

to the commands above or, using sed:
Code:
|xargs|sed -e s'/ /,/g'

 

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