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Top Forums UNIX for Dummies Questions & Answers Date conversion
# 8  
Old 08-04-2009
In order they are file permissions, number of hardlinks, user, group, size, date, and filename. The -a part doesn't change the fields, just the -l; without that, it would just list files with no information about them.
# 9  
Old 08-06-2009
Hi,

I have a variable $c_start=17-JUL-2009 03:45:59, i need to convert it to
17-07-2009 03:45:59, I saw your example but it works only when using ls,
however I have taken this value out of a logfile.

Any ideas on how to do it ?

regards
Happyrain

---------- Post updated at 12:08 PM ---------- Previous update was at 11:59 AM ----------

Hi,

I ve done that using `date -d "$c_start" +"%d-%m-%y %H:%M:%S"`

It converts from 17-JUL-2009 03:45:59 to 17-07-09 03:45:59.

Thnx.
 

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