UNIX for Dummies Questions & Answers

hi, i have a very long text file. i need to extract with grep command a certain part.
for example text file include 1ooo rows:
1....
2...
3...
.
.
.
1000

i want to view with grep only rows 50-100.
any ideas will be appreciated
thanks...

why you want to do it with grep only??
sed,awk many other simple commands can do it.. read the man pages and give it a try..

Hi.

Grep is for searching for specific things. If you only want specific lines, not based on the contents you could, amongst other things, use head and tail..

Code:

head -100 file | tail -50

thanks mate, in order to use your solution i need another piece of the puzzle:
lets say that i know the first row number (e.g. 50) but i need to find out the number of the bigger one. the only clue i have is that row 100 is starting with certain string (x).
between 50-100 x appears only on the 100 row, though after 100 it appears on various rows. do you have an idea how can i locate the number of that row?
-----------------------------------------------------------------------
BTW i need this section for manipulating it in my bash script...
if you can help it will be highly appreciated.

Code:

nawk 'FNR==50,/^x/' myFile

Yep, that's good!

And by the same definition, so is

Code:

awk 'FNR==50,FNR==100' myFile

I do love this forum!

thanks folks but it seems the it just opens the file (as cat).

hoped it will retrieve the row's number.

thanks...