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Cut Command value assign to variable

 
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# 1  
Old 06-18-2009
Cut Command value assign to variable
Hi,
I am new to UNIX Scripting. I have been trying to use the CUT command to retrieve part of the header from a file and assign it to a variable. I have tried searching a lot, but I am still unsuccessful.

Sample Header: HJAN BALANCE 20090616
I need to retrieve the date here, which always ranges from the 18-25 position.

All I am trying to do is:

echo "Header Line: $headerLine"
headerDate = cut -c18-25 ${headerLine}

Here $headerLine has a valid value. But the command doesnt work.

Kindly assist.

Thanks,
Raghu
# 2  
Old 06-18-2009
Try...
Code:
headerDate=`cut -c18-25 ${headerLine}`

# 3  
Old 06-18-2009
Thank you Rakesh.
I tried this. Below is the response:

Header Line: HJAN BALANCE 20090616
cut: cannot open HJAN
cut: cannot open BALANCE
cut: cannot open 20090616
Launch_LKW-Gen.ksh[136]: headerDate: not found
Header Date:
# 4  
Old 06-18-2009
Try...
Code:
headerDate=$(expr substr "${headerLine}" 18 8)

# 5  
Old 06-18-2009
Following is the response:

Header Line: HJAN BALANCE 20090616
expr: syntax error

Does it have to do with the double quotes?
Last edited by ragz_82; 06-18-2009 at 02:39 AM.. Reason: Typo
# 6  
Old 06-18-2009
headerDate=`echo $headerLine | cut -c18-25`
# 7  
Old 06-18-2009
Amit,
This option worked. But the results are not as expected and also varies for different inputs. Kindly take a look:

Header Line: HJAN BALANCE 20090616
Header Date: 0616
Header Line: HJAN HOLDING 20090616
Header Date: 0616
Header Line: HJAN CASHLEDGER20090616
Header Date: 090616
 
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