Login or Register to Ask a Question and Join Our Community


UNIX for Dummies Questions & Answers

Cut Command value assign to variable

 
Thread Tools Search this Thread
Top Forums UNIX for Dummies Questions & Answers Cut Command value assign to variable
# 8  
Old 06-18-2009
Quote:
Originally Posted by rakeshawasthi
Try...
Code:
headerDate=`cut -c18-25 ${headerLine}`

My mistake
Code:
headerDate=`echo ${headerLine} |cut -c18-25`

Results are not as expected because you are not having date from columns 18 to 25...Earlier you said, it is fixed.
# 9  
Old 06-18-2009
I got the reason after I posted the previous one. The separators between the three values is a TAB and not multiple spaces. I realized when I pasted the output here. There is only one space now, which is actually a TAB.

May be I should use the -d option and retrieve the 3rd value?

Following is the content of the first line of the file:
HJAN BALANCE 20090616
# 10  
Old 06-18-2009
echo $headerLine | cut -d ' ' -f3 | cut -c5-8

If the date is in third column and each column is separated by white space.
# 11  
Old 06-18-2009
Thank you Amit, this helped.

The possible inputs are following:
HJAN BALANCE 20090616
HJAN HOLDING 20090616
HJAN CASHLEDGER20090616

Hence it worked for the first two. Hence I feel in my case the best approach would be to retrieve the last 8 characters. But since there are trailing spaces, I need to first trim the line then retrieve the last 8.

Makes sense?
 
Login or Register to Ask a Question

Previous Thread | Next Thread

10 More Discussions You Might Find Interesting

1. UNIX for Beginners Questions & Answers

Assign a command to a variable - Help

Hi, I have the script below. When i assign SSH_COMMAND to "ssh -o ConnectTimeout=2 ${SERVER} ${AS_SUDO} ${COMMANDS}" and then execute it as ${SSH_COMMAND} I get the following error: ssh: Could not resolve hostname sudo: Name or service not known ssh: Could not resolve hostname sudo: Name or... (3 Replies)
Discussion started by: mohca2020
3 Replies

2. UNIX for Beginners Questions & Answers

How do I assign the output of a command to a variable within a loop in bash?

In the else of the main if condition . else set lnk = $(readlink -f <path> | cut -d '/' -f7) echo "$lnk" if ] When I run the above on command line , the execution seems to be fine and I get the desired output. But when I try to assign it to a variable within a loop... (12 Replies)
Discussion started by: sankasu
12 Replies

3. UNIX for Beginners Questions & Answers

Need to pass variable in a command and assign value to a variable

Hello All, Hope you're doing well ! I am trying below command to be passed in a shell script, header_date_14 is a variable and $1 is the name of a file I intend to pass as a command line argument, however command line argument is not being accepted. header_date_14=$(m_dump... (8 Replies)
Discussion started by: ektubbe
8 Replies

4. Shell Programming and Scripting

How to assign value to variable using cut?

Hey guys. Below is the command I am using to assign "yellow" to the variable yellow. I can seem to echo it out using xargs but when I assign it to yellow and then try to echo it out it prints a blank line. Below is the command. Your help is highly appreciated! cut -c 2- color.txt |... (11 Replies)
Discussion started by: eldan88
11 Replies

5. Shell Programming and Scripting

Assign the result of a multiline command to a variable

Hi, I have the following command that lists all the .o files from all the directories except of vwin (which I don't want it) for i in `ls -d */*.o|awk '$0 !~ "vwin"'`; do echo $i; done The result is something like that dir1/file1.o dir1/file2.o dir2/file3.o etc. So, I want to create a... (9 Replies)
Discussion started by: scor6800
9 Replies

6. Shell Programming and Scripting

Unable to assign command output to variable

Code set -x STATUS="0" echo $STATUS for i in `ls -ltr Report*|awk '{ print $9 }'` do if then flg = "`head -1 "$i" |cut -c 31-33`" echo `head -1 "$i" |cut -c 31-33` echo $flg if then echo "having Fun" STATUS="2" else echo "no Fun" fi fi (2 Replies)
Discussion started by: Funkeydude
2 Replies

7. Shell Programming and Scripting

Assign command (with pipe) output to a variable

Hi , I would like to assign command (with pipe) output to a variable. The code is as follows. The goal of the code is to get the last folder folder with a particular name pattern. myDate=`ls | grep 2009 | tail -1` echo "myDate=" $myDate However, in the presence of the pipe, the code... (3 Replies)
Discussion started by: jeff_cen
3 Replies

8. Shell Programming and Scripting

How to assign the result of a SQL command to more than one variable in shell script.

Hi Friends... Please assist me to assign the result of a SQL query that results two column, to two variables. Pls find the below code that I write for assigning one column to one variable. and please correct if anything wrong.. #! /bin/sh no=' sqlplus -s uname/password@DBname... (4 Replies)
Discussion started by: little_wonder
4 Replies

9. Shell Programming and Scripting

Assign bash command to variable

Hi I am trying to write a function that needs to be able to assign the last run shell command to a variable. The actual command string itself not the exit code of the command. I am using the bash command recall ability to do this as follows: alias pb='ps | grep ash' ... (3 Replies)
Discussion started by: Moxy
3 Replies

10. Shell Programming and Scripting

assign awk command result to a variable

#!/bin/sh # ## MYSTRING = `awk '/myApp.app/' /Users/$USER/Library/Preferences/loginwindow.plist` if then echo String not found defaults write /Users/$USER/Library/Preferences/loginwindow AutoLaunchedApplicationDictionary -dict-add -string Hide -bool YES -string Path -string... (9 Replies)
Discussion started by: dedmakar
9 Replies
Login or Register to Ask a Question