UNIX for Dummies Questions & Answers

I try to run a script as background job.

script:
#!/usr/bin/csh
/usr/bin/date +20%y-%m-%d > ~/datsql.txt

If I start it I got this output:
tac> ./datermitteln&
[5] 293
[5] + Stopped (SIGTTOU) ./datermitteln&

I insert the following line inside my script, but without any advancement.
stty -tostop

Please help!
regards joerg

It looks to me that your script only executes one "date" command and stops then....

What exactly are you trying to do with it?

With only one line it will execute immediately and then be finished...

If you want it to run indefinitely do this.

# vi datermitteln
while true
do
/usr/bin/date +20%y-%m-%d
done



However, that is a very strange command... If you are trying to capture this for another script, just assign it to a variable...


# DATE=`/usr/bin/date +20%y-%m-%d` # backtics btw...
# echo $DATE
2003-09-05

Kelam,

Joerg's issue seems to be with the job stopping - I had to set in the script to turn tostop on (stty tostop ) to get the script to have the same issue as Joerg. Unfortunately, I haven't had time to get back to it.

Joerg, I tried this on Solaris and HP-UX and could not make the job stop unless I set tostop (instead of turning it off like you were trying). What OS are you using?

RTM, that was my point ... the script WILL stop b/c it only runs one command.

Maybe I am misunderstanding his problem... Does he want it to keep running or to stop running?

I cant find a use for this script myself... why not make it a variable in a script?