Quote:
Originally Posted by
coyote1967
Oh cool thanks Jim. I might be back with more questions
OK more questions LOL
So what everybody is saying is that if [$# -lt 1]; then set /etc/ /etc/.save; fi
if the $# is less than 1 then set will show the variables in the /etc/ file? right??? then how does the /etc/.save come into play?
The next line in the code is almost like the one I just posted except that it says
if [$# -lt 2] then set $* /etc/.save; fi
So if the argument count is less than 2 then it will show the variables in the $*????? I know the "*" is a metacharacter but there again how or what is it doing to the /etc/.save file? This stuff is making my head spin. It seems way over my head and I am supposed to learn it. There are just too many special characters that doing different things at different times and it is confusing the hell out of me. I thought C++ was bad but this takes the cake.