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Formatting a month's name

 
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# 1  
Old 05-02-2009
Formatting a month's name
The following snippet should output the full month name and the month number:
Code:
#!/bin/sh
echo "Name of the month: " `date +%B` $1

The result is something like:
Name of the month: May 03
whereas I want the argument $1 to be processed and returned, so that it will result in something like:
Name of the month: March 03
How do I provide $1 as input to the date function?
# 2  
Old 05-02-2009
This will give you the expected result

Code:
let mon=$1-1
date "+%B" --date "1970-01-01 UTC $mon months"

# 3  
Old 05-03-2009
Actually I just need the name of the month that was provided as the argument, so 01 will yield January, 02 will yield February and so on.
# 4  
Old 05-04-2009
You should not use the "date" command for that, because most versions of the "date"-command will not accept any input at all. The GNU-date used in Linuxes is a rare exception to this rule.

But as there are not to many months you could use a simple "case". Package it into a function for maximum encapsulation:

Code:
function month_name
{
typeset name=""

case "$1" in
     "01") name="January" ;;
     "02") name="February" ;;
     "03") name="March" ;;
     "04") name="April" ;;

     ....
esac

print - "$name"

return 0
}

I hope this helps.

bakunin
# 5  
Old 05-04-2009
i hope bakunin - solution will help you.

If you want the solution should be implemented with the date command, then the solution which i posted might help you. If you don't understand that, here am rewriting it exactly as:

Code:
#!/bin/sh
let mon=$1-1
echo "Name of the month: " `date "+%B" --date "1970-01-01 UTC $mon months"`

I believe It fully satisfies your requirement as:
Code:
$ sh month.sh 3
Name of the month:  March
$ sh month.sh 10
Name of the month:  October

# 6  
Old 05-05-2009
@bakunin: I was getting concerned that a case statement would be necessary

@thegeek: For the record, this is the error message that I am getting:
Code:
# ./month.sh 10
9
date: illegal time format
usage: date [-jnu] [-d dst] [-r seconds] [-t west] [-v[+|-]val[ymwdHMS]] ... 
            [-f fmt date | [[[[[cc]yy]mm]dd]HH]MM[.ss]] [+format]
Name of the month: 
# ./month.sh 03
2
date: illegal time format
usage: date [-jnu] [-d dst] [-r seconds] [-t west] [-v[+|-]val[ymwdHMS]] ... 
            [-f fmt date | [[[[[cc]yy]mm]dd]HH]MM[.ss]] [+format]
Name of the month:

I have tried multiple variations to the script, but none that worked so far. Please advise.

Code:
# uname -a
FreeBSD 7.1-RELEASE FreeBSD 7.1-RELEASE #0: Thu Jan  1 14:37:25 UTC 2009     root@logan.cse.buffalo.edu:/usr/obj/usr/src/sys/GENERIC  i386

# 7  
Old 05-05-2009
This is what I have at the moment. Not a pretty sight and it does not feel like the UNIX approach:
Code:
#!/bin/sh

case "$1" in
	"01") name="January" ;;
	"02") name="February" ;;
	"03") name="March" ;;
	"04") name="April" ;;
	"05") name="May" ;;
	"06") name="June" ;;
	"07") name="July" ;;
	"08") name="August" ;;
	"09") name="September" ;;
	"10") name="October" ;;
	"11") name="November" ;;
	"12") name="December" ;;
	* ) name="Not a valid month number." ;;
esac
echo "$name"
	
return 0

 
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