I'm trying to write shell script that when invoke, has 2 arguements, or 1.
If there's one arguement, then that's the process name. If there's 2, then one is the timeout.
USAGE: Assign1.sh <process> <timeout>
If no timeout was set, then the default timeout is 15 minutes.
So after it read the process and time out, then it check how long the process has been running, then check with the current time to see if it's been 15 minutes. If it has, then it kill the process, if it hasn't, then it exit.
Here's my script:
Code:
#!/bin/sh
#
#
if test $# -eq 2; then
timeout=$2
elif test $# -eq 1; then
timeout=15
else
echo "\tUsage: $0 <process> <timeout>"
fi
echo $timeout
USERNAME=`who am i | cut -f1 -d" "`
STIME=`ps -u $USERNAME -f | grep $1 | awk -F" " '{print$5}'`
STIME=`echo $STIME | awk -F" " '{print $2}'`
STIME=`$STIME | awk -F: '{print $1*60+$2}'`
PID=`ps -u $USERNAME -f | grep $1 | awk -F" " '{print$2}'`
PID=`echo $PID | awk -F" " '{print $2}'`
current_time=`date | awk -F" " '{print $4}'`
current_time=`$current_time | awk -F: '{print $1*60+$2}'`
timediff=`$current_time-$STIME`
if test $timediff -lt $timeout; then
echo "$1 has not ran for $timeout yet."
else
echo "Kill $PID"
No idea why it's not working! :-(
Any help would be greatly appreciated
I'm trying to write shell script that when invoke, has 2 arguements, or 1.
If there's one arguement, then that's the process name. If there's 2, then one is the timeout.
USAGE: Assign1.sh <process> <timeout>
If no timeout was set, then the default timeout is 15 minutes.
So after it read the process and time out, then it check how long the process has been running, then check with the current time to see if it's been 15 minutes. If it has, then it kill the process, if it hasn't, then it exit.
Here's my script:
Code:
#!/bin/sh
#
#
if test $# -eq 2; then
timeout=$2
elif test $# -eq 1; then
timeout=15
else
echo "\tUsage: $0 <process> <timeout>"
fi
echo $timeout
USERNAME=`who am i | cut -f1 -d" "`
STIME=`ps -u $USERNAME -f | grep $1 | awk -F" " '{print$5}'`
STIME=`echo $STIME | awk -F" " '{print $2}'`
STIME=`$STIME | awk -F: '{print $1*60+$2}'`
PID=`ps -u $USERNAME -f | grep $1 | awk -F" " '{print$2}'`
PID=`echo $PID | awk -F" " '{print $2}'`
current_time=`date | awk -F" " '{print $4}'`
current_time=`$current_time | awk -F: '{print $1*60+$2}'`
timediff=`$current_time-$STIME`
if test $timediff -lt $timeout; then
echo "$1 has not ran for $timeout yet."
else
echo "Kill $PID"
No idea why it's not working! :-(
Any help would be greatly appreciated
STIME=`echo $STIME | awk -F" " '{print $2}'` # what is the purpose of this??
STIME=`$STIME | awk -F: '{print $1*60+$2}'` # you have to put as echo $STIME before piping it to awk..
I fixed the echo $STIME thing.
The second one was to pick the second time. I noticed sometime it output two or three times... like there was two or three process of the same name running. I chose the second one because it always seem to have a lower time, meaning it's been running the longest.
Here's what I get when I run "sh -x assign1.sh bash 20"
Code:
sh -x assign1.sh bash 20
+ test 2 -eq 2
timeout=20
+ echo 20
20
+ who am i
+ cut -f1 -d
USERNAME=std11
+ ps -u std11 -f
+ grep bash
+ awk -F {print$5}
STIME=14:37:31
14:44:55
14:44:55
+ echo 14:37:31 14:44:55 14:44:55
+ awk -F {print $2}
STIME=14:44:55
+ echo 14:44:55
+ awk -F: {print $1*60+$2}
STIME=884
+ ps -u std11 -f
+ grep bash
+ awk -F {print$2}
PID=6304
6438
6428
+ echo 6304 6438 6428
+ awk -F {print $2}
PID=6438
+ date
+ awk -F {print $4}
current_time=14:44:54
+ 14:44:54
assign1.sh: 14:44:54: not found
+ awk -F: {print $1*60+$2}
current_time=
+ -884
assign1.sh: -884: not found
timediff=
assign1.sh: syntax error at line 26: `end of file' unexpected
It looks like my current_time became negative somehow???
Beware of fuzzy matching with grep. In this line the parameter $1 could match any like number in the "ps -fu $USERNAME" output. For example the parent PID of a subprocess or say some part of the cpu usage. In this form of grep it would find "12" in "61234" or in "12:46".
Tip: "ps -fp${process_id}" would give you the status of that one process.
Sorry to be unhelpful but I believe that this script design is fundamentally flawed because "ps" changes the date format as processes get older and this changes the positional parameters presented to awk.
Login as root have a look at "ps -ef" on a system which has been up for more than 24 hours.
Last edited by methyl; 04-04-2009 at 10:09 PM..
Reason: tags displaced
the "sh -x" REALLY HELPS, it's like a debug almost? run one line at a time and shows me the output and everything. Very neat to know.
I realized that the STIME and CURRENT_TIME were both saved as strings, so they cant be compute... when they do, the output was null, so it never worked.
I changed them to int with typeset -i and it worked. Woo!
Probably not very good coding... but it works... I'll figure out a different approach later.
the "sh -x" REALLY HELPS, it's like a debug almost? run one line at a time and shows me the output and everything. Very neat to know.
I realized that the STIME and CURRENT_TIME were both saved as strings, so they cant be compute... when they do, the output was null, so it never worked.
I changed them to int with typeset -i and it worked. Woo!
Probably not very good coding... but it works... I'll figure out a different approach later.
good you understand the imp of "sh -x"
way to go buddy!!!
regards,
vidya
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