awk help


 
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# 8  
Old 02-16-2009
Quote:
Originally Posted by d_kowalske
This might be a dumb question but I dont think I have the nawk command. Can this be run using just awk.
I am new to our system and it says nawk command not found
yes, use 'awk' instead.
# 9  
Old 02-16-2009
Quote:
Originally Posted by d_kowalske
This is the format of the file. The output can be the same. I just need to extract the entire line with "start", and a value in the fourth column, and all of the following info until the next "start" for the entire file. Im sorry this might be confusing, I am very new to this.

start -71.50000 40.37000 1981 1 7 8 1
0.00000 7.43000 9999.00000
25.00000 7.50000 9999.00000
45.00000 7.51000 9999.00000
60.00000 7.68000 9999.00000
64.00000 8.72000 9999.00000
66.00000 10.13000 9999.00000
69.00000 10.82000 9999.00000
81.00000 10.83000 9999.00000
start -71.52700 40.15500 1981 1 7 7 2
0.00000 9.51000 9999.00000
4.00000 9.39000 9999.00000
35.00000 9.39000 9999.00000
64.00000 9.46000 9999.00000
68.00000 10.69000 9999.00000
70.00000 10.94000 9999.00000
85.00000 10.98000 9999.00000

I hope this comes through alright
Once again, please use BB Codes when posting code/data samples.

Also please provide a sample of the expected output based on your sample input.
# 10  
Old 02-16-2009
Ok Ive tried to add some BB Codes, they are all new to me, I thought the bold strings could be used for searching in awk. I need the output to be identical to the input. I just only want data from 1970. There are an unknown number of lines after the line with start & 1970 I want them all if they are from 1970. Let me know if this helps clarify

start -71.50000 40.37000 1970 1 7 8 1
0.00000 7.43000 9999.00000
25.00000 7.50000 9999.00000
45.00000 7.51000 9999.00000
60.00000 7.68000 9999.00000
64.00000 8.72000 9999.00000
66.00000 10.13000 9999.00000
69.00000 10.82000 9999.00000
# 11  
Old 02-16-2009
Code:
awk '
/start.*1970/ {p=1;print $4;next}
/start/ && p {exit}
p' file

Regards
# 12  
Old 02-16-2009
ok, this is still not clear, but.....
Code:
awk '
   /^start/ && $4=="1970" {p=1}
   /^start/ && $4 !="1970" {p=0}
   p' file

# 13  
Old 02-16-2009
Quote:
Originally Posted by vgersh99
ok, this is still not clear, but.....
Code:
awk '
   /^start/ && $4=="1970" {p=1}
   /^start/ && $4 !="1970" {p=0}
   p' file

That seems to work! Sorry about all the confusion. Did I use BB codes correctly? I am mostly a windows user and never used them before.
Thanks
# 14  
Old 02-16-2009
Quote:
Originally Posted by d_kowalske
That seems to work! Sorry about all the confusion. Did I use BB codes correctly? I am mostly a windows user and never used them before.
Thanks
No, you need to use [code] code/data goes here[/code] paradigm. Reread the posted link.
 
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