awk or sed


 
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# 1  
Old 03-28-2019
awk or sed

Hi, I need a help.

I have the following log file entries

Code:
[28 Mar 2019 13:11:48,576] [Nsh-Proxy-Thread-102] [INFO] [admhowdy@blog.com:UNIXAdmins:100.0.0.1] [ROSSOPRO
XY] Connected to srtmm.blog.com with a socket descriptor 344

I want the date "28 Mar 2019 13:11:48,576" and username admhowdy@blog.com and ip address 100.0.0.1.

How to achieve this?

Thanks,
Dinesh
# 2  
Old 03-28-2019
Well, at least, you should show us some attempts at the problem.

Try this awk
Code:
awk ' {gsub("\\[|\\]","",$0); split($7,a,":"); date=$1 FS $2 FS $3 FS $4; print date, a[1], a[3] } ' <your file>

Regards
Peasant.
This User Gave Thanks to Peasant For This Post:
# 3  
Old 03-28-2019
Thank you very much. Next time I will post what I tried.
# 4  
Old 03-29-2019
gsub("\\[|\\]", "", $0) can be simplified gsub("[][]", "")
Explanation: in a RE a [ ] character set cannot be empty so an immediate ] is a character. And $0 is default in sub() and gsub().

A good alternative is to use this RE as a field separator; then the even fields $2 $4 ... are within the square brackets:
Code:
awk -F '[][]' '{ split($8, a, ":"); print $2, a[1], a[3] }' filename

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