UNIX for Advanced & Expert Users

Hey all,

Can I put sed command inside the awk action ?? If not then can i do grep in the awk action ??

For ex:

awk '$1=="174" { ppid=($2) ; sed -n '/$ppid/p' tempfind.txt ; }' tempfind.txt

Assume: 174 is string.
Assume: tempfind.txt is used for awk and sed both.

tempfind.txt contains :

t2589vg 8888 11234 -ksh
mqsiadm 128 134 -ksh
mqsiadm 174 8888 -ksh



Please let me know, its an urgent.
Thanks to all brains.

You can give your opinion/examples/suggustions regarding the same (to use: sed in awk or grep in awk or nested awk).

Varun.

Code:

$ fpm=`awk '$2=="174"  { print $3 }' tempfind.txt` | sed -n /$fpm/p tempfind.txt
t2589vg 8888 11234 -ksh
mqsiadm 174 8888 -ksh
$

Code:

awk 'BEGIN {
  while (getline < "file")
     if ($2 == 174)
        ppid = $3
} {
  if ($0 ~ ppid) 
     print
}' file

Hey murphy,

Thnks for the reply firstof all.

Below is my script :
where i am using your given code..and somehow its not giving desired o/p.
can you please tell me what is wrong in this...

-----------------------------------------------------------------------

#SCRIPT TO CHECK WHO HAS ACCESSED THE LOG/FILE IN PAST 'N' MINUTES, AND MAIL ACCORDINGLY.

MYPATH="/clocal/mqbrkrs/user/mqsiadm/sanjay/"
MAIL_RECIPIENTS="vg517@dcx.com"
Subject=":: File(s) accessed/touched in last few minutes ::"
>tempmail.txt
>tempfind.txt
>filterfile.txt
>tempgrep.txt
#*************************************************************************************************** ****************************************************
## List all the files which one accessed since last 1 min #####
#*************************************************************************************************** *****************************************************


ps -ef | grep "\-ksh" | awk '$8 !~ /grep/ { printf "%s %s %s %s %s\n", $1, $2, $3, $5, $8 ; }' >> ./tempfind.txt

for file_dir in `find $MYPATH -amin -1`
do

echo `fuser -uf "$file_dir" ` >> temp.txt.$$
echo " $file_dir is being accessed" >> temp.txt.$$
done

sed -n '/^[ ][a-z]*/p' temp.txt.$$ >> tempmail.txt
echo "Accessed By: " >>tempmail.txt
sed -n '/^[0-9]/p' temp.txt.$$ > filterfile.txt

for pid_var in `awk '{ print $2 }' filterfile.txt`
do
fpm=`awk '$2=="$pid_var" {print $3}' tempfind.txt` | sed -n '/$fpm/p' tempfind.txt >> tempmail.txt

done

cat tempmail.txt | mailx -s "$Subject" "$MAIL_RECIPIENTS"


-----------------------------------------------------------------------

Its not giving anyting, I tried on commands prompt aswell.
Could you guide me, please.

Thanks
Varun.

Put the sed command inside double ticks as the single ones prevent variable expansion...

Code:

sed -n "/$fpm/p"

hey,

I tried using :
fpm=`awk '$2=="966906" {print $3}' tempfind.txt` | sed -n "/$fpm/p" tempfind.txt
but still its not working. Whenever I do only awk '$2=="966906" {print $3}' tempfind.txt it works and gives the value of $3, but when we assign $3 to fpm variable, its not going ahead.

Even i have tried..
fpm=`awk '$2=="966906" {print $3}' tempfind.txt` | echo "$fpm"
It does not show anything.

Where is the matter ?? Please suggust me, this is the last thing in my script and am waiting to complete it.

Thanks !!
Varun

Another method of solving the original question using getline

Code:

$cat awkfile
BEGIN { pid="" }

$2=="174" { pid=$3 }

END {
   if (pid != "") {
      tmp="sed -n /"pid"/p file"
      while ((tmp | getline) > 0)
         print
      close(tmp)
   }
}
$

Code:

$ awk -f awkfile tempfile.txt
t2589vg 8888 11234 -ksh
mqsiadm 174 8888 -ksh
$