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pattern matching in unix

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# 1  
Old 09-24-2008
pattern matching in unix
Task is to identify files like code.1 , code.23 and so on ... (the files which are ending with a number) but it should not match files like code.123abc. So the search will normally search for files with "code." and at the end we should extract for the correct match. Now I have to remove these files interactively i.e 'rm -i '. Now please let me know any oneliner in unix or perl to perform this task.
I tried : find . -name "code.[0-9]* -exec rm -i {} \; (but this will not work ..??)
# 2  
Old 09-24-2008
As find is not using Regular Expressions, you might want to use something like:

Code:
find . -print| grep code.[0-9]*$| xargs -p rm -i

# 3  
Old 09-24-2008
I see that grep is not a correct match .. even if that grep works ... I am unable to parse files and remove them interactively.
# 4  
Old 09-24-2008
Show your error message please. Also I don't understand what you mean by "grep is not a correct match". xargs -p and rm -i should ensure it will be interactively:

Code:
root@isau02:/data/tmp/testfeld> ls -la
insgesamt 8
drwxr-xr-x 2 isau users 4096 2008-09-24 11:11 .
drwxr-xr-x 7 isau users 4096 2008-07-09 14:36 ..
-rw-r--r-- 1 root root     0 2008-09-24 11:11 code.123
-rw-r--r-- 1 root root     0 2008-09-24 11:11 code.123abc
-rw-r--r-- 1 root root     0 2008-09-24 11:11 code.123.abc
root@isau02:/data/tmp/testfeld> find . -type f -print| grep code.[0-9]*$| xargs -p rm -i
rm -i ./code.123 ?...n
root@isau02:/data/tmp/testfeld>

# 5  
Old 09-24-2008
You could use several "-name" clauses for find to exclude the files you do not want:

Code:
find /some/dir -name "code.[0-9]*" ! -name "*[a-z]" -exec ....

The exclamation mark is a logical NOT. "! -name x" find everything except a file named "x".

I hope this helps.

bakunin
# 6  
Old 09-24-2008
Code:
ls -1 code.[0-9]* | egrep -E ".[0-9]+$" | xargs  rm

# 7  
Old 09-24-2008
Thanks bakunin this is working ... !
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