Passing blank arguments to a script

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# 1  
Old 01-08-2008
Passing blank arguments to a script

I have a cron job script that receives several command line arguments. At some point if there are validation problems and the job cannot be run, it duplicates the entire command line into a temporary text file which is later executed as a script. Unfortunately when I pass the list of received arguments (ie: $*) to this new file, the quoted blank arguments are dismissed.

For example, my script "" looks like this:
if [ some validation fails ]
echo "$0 $*" >>
exit 1

If was run as: one two '' four five

It will convert the 2 single quotes to a blank when exporting the line to, thus removing the blank argument.

Here's what looks like: one two four five

I need those single quotes to be passed. Any ideas anyone??

# 2  
Old 01-08-2008
There is actually an entry in the man page to explain exactly this situation; use "$@"
# 3  
Old 01-08-2008
How do you man "$@" ? It gives me errors:

->man "$@"
sh: @: Parameter not set.


# 4  
Old 01-08-2008
no, I mean man ksh.

"$@" is what you should use in your script instean of $*
# 5  
Old 01-08-2008
Oh sorry, I forgot the other bit, and use printf, not echo.

printf "'%s' " "$@" >> file
printf "\n" >> file

# 6  
Old 01-08-2008
Thanks for the tip - I never tried man on ksh - kool Smilie

Unfortunately either "$@" or "$*" produce an unquoted double space Smilie

How about trying to replace this double space with [space] [quote] [quote] [space]. The 'tr' command doesn't seem quite fit to handle this. Remains 'sed' but I am not very familliar with it. Please help with the correct syntax:

echo "$@"|sed ??? >>


# 7  
Old 01-08-2008
See my previous. I probably posted it while you were typing.
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