Shell Programming and Scripting

Hello

I have problem with reg-expr and function gsub();

File that I want to preprocess look like this:
int table [variable][variable];
printf(" variable : ", variable) ;

Using nawk I try something like this:
for ( .... )
{
line = $0
reg_expr = "[^\"][ a-zA-Z0-9\+\-\*\/\&\^\%\#\!\~\,\[\]\.\=]*" "" variable "" "[ a-zA-Z0-9\+\-\*\/\&\^\%\#\!\~\,\[\]\.\=]*[^\"]" ;
gsub( reg_expr ,'200',line)
print line
}

After preprocesing it should look like this :

int table[200][200];
printf("variable:", 200);


My program shouldn't change "variable" in function printf.
Main problem is with quotation marks .
After removing expresions like: " .. . . . .." , I can write :
gsub(variable ,'200', line ), and everything is fine .
Second problem with my reg_expr is that it's removes braces and other characters .

How to write proper reg-expr ?

I'm not sure that you can do all the work with a single regex.
A possible solution :

Code:

   Line = $0;
   while ( match(Line, /\"[^\"]*variable[^\"]*"|[0-9a-zA-Z_]variable|variable[0-9a-zA-Z_]/) ) {
      str = substr(Line, RSTART, RLENGTH);
      gsub(/variable/, SUBSEP, str);
      Line = substr(Line, 1, RSTART-1) str substr(Line, RSTART+RLENGTH);
   }
   gsub(/variable/, "200", Line);
   gsub(SUBSEP, "variable", Line);
   print Line;

Input:

Code:

/* test */
int another_variable;
int variable2;
int table [variable][variable];

printf(" variable  : ", variable) ;
printf(" variable2 :", variabl2) ;

Output:

Code:

/* test */
int another_variable;
int variable2;
int table [200][200];

printf(" variable  : ", 200) ;
printf(" variable2 :", variabl2) ;

Jean-Pierre.