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Extra output in the script

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# 1  
Old 11-27-2008
Extra output in the script
Hi ,

I am trying to execute the following script.

#!/bin/sh
find . -name "common.log.diff"
if [$? -eq 1]; then
cp common.log common.log.diff
diff common.log common.log.diff > DIFFERENCE.log
cp common.log common.log.diff
grep "ERROR" DIFFERENCE.log
if [ $? -eq 0 ]; then
echo "1"
else
echo "0"
fi
else
diff common.log common.log.diff > DIFFERENCE.log
cp common.log common.log.diff
grep "ERROR" DIFFERENCE.log
if [ $? -eq 0 ]; then
echo "1"
else
echo "0"
fi
fi


This is giving the following output.

./testscript
./common.log.diff
./testscript[3]: [0: not found.
0


In this " 0 " is fine. But I dont know why it is
giving

./common.log.diff &
./testscript[3]: [0: not found.

along with "0"

Kindly suggest. What wrong with my script ?

Regards
# 2  
Old 11-27-2008
Change

Quote:
if [$? -eq 1]; then
to

Code:
if [ $? -eq 1 ]; then

Also please use code tags.
# 3  
Old 11-27-2008
let me check
# 4  
Old 11-27-2008
No w it is giving the following output

./common.log.diff
0

what to do so that I dont get

./common.log.diff

I want only " 0 " as output

Kindly suggest
# 5  
Old 11-27-2008
Code:
find . -name "common.log.diff" > /dev/null 2>&1

# 6  
Old 11-27-2008
Yes !!!!!

It worked !!!

Thanks a Lot . U helped me a lot.

Regards
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