Shell Programming and Scripting

I have a list of ids and a master list. I need to display entries from the master list matching ids in the first list. The master list is space delimited, id is 1st field.

$ cat id_list
2010
7
51

$ cat master_list
1 one detail1 detail2
2 two detail1 avg1 detail2 avg2
... etc ...

There are not more than 1000 entries in master_list and around 100 entries in id_list.

My code:

Code:

 
for id in $( cat id_list ); do 
awk -e'{ if($1 == xid){print}}' -v xid=$id master_list
done

results:
2010 two thousand and ten detail1 detail2 avg1 avg2
7 seven detail1 detail2
51 fifty one avg-step-1 avg-step-2

It works, but I suspect ther are much better solutions without calling awk in the loop. Any ideas?

How about this ?

Code:

cat id_list | while read line ; do grep $line master_list ; done

CMIIW, YMMV

HTH

No, grep would not work, as i need exact match of id field.
To clarify, imagine that my id_list has id = 1, then all lines in master list having '1' anywher within them would be selected.

If the id_list and master_list have the field = 1 at the beggining of the line (always first field of each line).
the script should be :

Code:

cat id_list | while read line ; do grep ^$line master_list ; done