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path of the running script

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# 15  
Old 11-14-2008
I see, I think this should work then:

Code:
#!/bin/bash
dirname $(which $0)

If you require the path including the filename, this should suffice:
Code:
#!/bin/bash
which $0

# 16  
Old 11-15-2008
I had this idea and thought it was great for a certain time untill I found a failure.
Consider the following script named test in your home directory:
Code:
#!/bin/bash
which $0

And now type the following commands:
Code:
$ ./test
/home/santiago/test
$ bash test
/usr/bin/test

The problem comes from the fact that there is another exe named test in the PATH.
Last edited by radoulov; 11-15-2008 at 05:47 AM..
# 17  
Old 11-15-2008
Quote:
Originally Posted by chebarbudo
What I want is to be able to know the address (full path) of the script that is currently running without knowing how the user called it.

Thank you for your proposal Scrutinizer but once again, this is a script that will fail in some cases :
Code:
# /bin/s
/bin
# s
/bin
# bash s
/root

In the last case, this command fails.
So far the only command I found that works all the time is my own insanely complicated one.
It seems you can use the non-standard command realpath.
If I'm not missing something again it's quite easy in this case ...

Code:
% ./s
/home/radoulov/t
% bash s
/home/radoulov/t
% /home/radoulov/t/../../radoulov/t/s
/home/radoulov/t
% . s
/home/radoulov/t
% cat s
#! /bin/sh

p="$(realpath "$0")"

printf "%s\n" "${p%/*}"

# 18  
Old 11-15-2008
Quote:
Originally Posted by chebarbudo
I had this idea and thought it was great for a certain time untill I found a failure.
Consider the following script named test in your home directory:
Code:
#!/bin/bash
which $0

And now type the following commands:
Code:
$ ./test
/home/santiago/test
$ bash test
/usr/bin/test

The problem comes from the fact that there is another exe named test in the PATH.
This is correct, if it's in the path before your script, it IS the real running program when invoked as you describe.
Last edited by radoulov; 11-15-2008 at 06:04 AM..
# 19  
Old 11-15-2008
Quote:
Originally Posted by radoulov
This is correct, if it's in the path before your script, it IS the real running program when invoked as you describe.
Not quite true:
Code:
~# cat /root/s
#!/bin/bash
echo "I'm a user created script stored in /root/"
which $0
~# cat /usr/local/bin/s
#!/bin/bash
echo "I'm a user created script stored in /usr/local/bin/"
which $0
~# bash s
I'm a user created script stored in /root/
/usr/local/bin/s

# 20  
Old 11-15-2008
Quote:
Originally Posted by radoulov
It seems you can use the non-standard command realpath.
If I'm not missing something again it's quite easy in this case ...

Code:
% ./s
/home/radoulov/t
% bash s
/home/radoulov/t
% /home/radoulov/t/../../radoulov/t/s
/home/radoulov/t
% . s
/home/radoulov/t
% cat s
#! /bin/sh

p="$(realpath "$0")"

printf "%s\n" "${p%/*}"

Counter example:
Code:
~# cat /usr/local/bin/s
#! /bin/sh
echo "I'm a user created script stored in /usr/local/bin/"
p="$(realpath "$0")"
printf "%s\n" "${p%/*}"
~# bash s
I'm a user created script stored in /usr/local/bin/
s: No such file or directory

# 21  
Old 11-15-2008
Quote:
Not quite true: ...
Quote:
Counter example: ...
Good points. You're right. So, as far as your initial question is concerned, _I_ have not a simpler solution.
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