Shell Programming and Scripting

hi i have a file with content, i need to extract last column from each line including spaces and form a string
i used echo "$LINE" | awk '{print $1,$2}' | grep '^\[' | awk '{printf("%-16s",$2)}' , but i am not getting the last 000000 and spaces



[00000000:00000000] 33333030 30303030 30303030 CTL1330000000000
[00000016:00000010] 44453932 33353237 36333030 0000DE9235276300
[00000032:00000020] 30305453 30353934 44453932 008000TS0594DE92
[00000048:00000030] 3633414D 45583030 30302E54 352763AMEX0000.T
[00000064:00000040] 20202020 20202020 20202020 RN
[00000080:00000050] 20203030 38303030 30303030 008000000
[00000096:00000060] 30303030 30300D 000000.


please help

thanks
Satay

Code:

awk '/^\[/ {print $NF}' infile

hi zaxxon, thanq for ur reply
i did not under stand, can u elaborate

Code:

/^\[/

This pattern should be clear - you used it yourself(?). Since it's in front of the curled brackets, it triggers the commands in the curled brackets when found/true.

Code:

{print $NF}

This one prints out the field and NF is the number of fields it replaces NF with the number of fields in this line which is the last field then automatically.

thanx zaxxon , can u tell how to form a string with the above data incoding spaces lke

CTL13300000000000000DE9235276300008000TS0594DE92352763AMEX0000.TRN 008000000 000000.
i am trying a lot , but i could not ,please help

Satya