How to compare the dates..


 
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# 1  
Old 10-22-2008
How to compare the dates..

Hi all,

I've written a script which gives the below information...

End Date&Time: 2008-10-21 10.54.37

Now i want to calculate this time with the current time.. and if its more than 48 hours past with the current time it should echo "48 Hours back"

Please help me..

thanks in advance..

# 2  
Old 10-22-2008
Hammer & Screwdriver Maybe a different way to approach this task

I can determine 'seconds since Epoch' on a file modification
Code:
> touch file286
> stat -c%Y file286
1224687447

Touch'ed another file a little later - note greater number
Code:
> touch file287
> stat -c%Y file287
1224687482

Now I can see that 35 seconds actually elpased
Code:
> echo `stat -c%Y file287` - `stat -c%Y file286` | bc
35

So, by extension, you could touch a temp file (like my file287) and then compare the number of seconds difference. Just do the math to figure out how many seconds in your desired elapsed time period.

Last edited by joeyg; 10-22-2008 at 12:03 PM.. Reason: corrected spelling
# 3  
Old 10-22-2008
The problem here is..?

When the dates are not matching... it could be a problem...


Guess this could not work...


Hope we have to find the current date and matching with the log file date.. and subtract and if less than blah blah then + or - 86400...

dont know how to write the same...

Please help...
# 4  
Old 10-22-2008
Since you said you had a script which gives ending date/time... figured you could
Code:
>touch /home/user/script_123.done

as the final command

Then your new script could
Code:
>touch /home/user/script_123.restart

And then do the math like I previously showed to see if the elapsed seconds had in fact elapsed.

Code:
>time_elap=$(echo `stat -c%Y script_123.restart` - `stat -c%Y script_123.done` | bc)

Now, just do an if-then for your time calculation and possible next steps.
# 5  
Old 10-22-2008
joeyg's answer is MUCH easier than coding this:
Code:
#!/bin/ksh

# two parms
# $1 = number of hours
# $2 = date in YYYY mm dd hh mi ss format
# prints  1 if date is older than  now minus <number of hours>
# prints 0 when not older
isolder()
{
	ago="$1"
	echo "$2" | sed 's/\./ /g' | sed 's/-/ /g' | read dt
	perl -e  ' 
	        use Time::Local;
	        $then = time - ( $ARGV[0] * 3600);
	        $testtime =
	           timelocal( $ARGV[6], $ARGV[5], $ARGV[4],
	                      $ARGV[3], $ARGV[2]-1, $ARGV[1]-1900);
	        $result = 0;
	        if ( $testtime < $then )
	        {
	            $result = 1;
	        }
            print "$result\n";
	        '  $ago  $dt
}

dt="2008-10-21 10.54.37"
# sample usage:
result=$(isolder 48 "$dt" )
if [[ $result -eq 1 ]] ; then
  echo "$dt is older than 48 hours"
else
  echo "$dt is not older than 48 hours"  
fi  
dt="2008-10-19 10.54.37"
result=$(isolder 48 "$dt" )
if [[ $result -eq 1 ]] ; then
  echo "$dt is older than 48 hours"
else
  echo "$dt is not older than 48 hours"  
fi

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