variables in a script

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# 1  
Old 10-01-2002
Question variables in a script


I have a variable (var) which can be any number. I would like to use the cut command on a string depending on the variable.

echo $string | cut -c 1-$var

This doesn't work as cut sees $var as $var rather than as 4. Can anyone suggest how I can evaluate $var in the cut command so cut sees $var as 4 ?

Many thanks
# 2  
Old 10-01-2002
The exact code that you posted works fine for me. I can't imagine why you're having trouble with it.
# 3  
Old 10-01-2002
Hi Perderabo,

I get "cut: The list arguments following the c option are not correct." from my script.

Although I did a quick command line test and it worked ok.
# 4  
Old 10-01-2002
You must have some other problem. Maybe "var" has some other value. Do a:
echo var = $var
before the cut statement.
# 5  
Old 10-01-2002
As the code stands in my script I'm doing the following

string2=`echo $string | cut -c1-c$length`

I did an echo of the whole line just before I executed the line

echo "string2=\`echo $string | cut -c1-c$length\`"
string2=`echo $string | cut -c1-c$length`

and ran the script again

I got

string2=echo 524286918 | cut -c1-c6
cut: The list arguments following the c option are not correct.

The line which was output is how I wanted it to look but I still get the error message

I've tried running it both under sh and ksh

it's a bizzare one!
# 6  
Old 10-01-2002
Originally posted by Bab00shka

string2=`echo $string | cut -c1-c$length`
You want "cut -c1-$length". Lose that "c" directly in front of the variable.
# 7  
Old 10-01-2002

Thanks Perderabo
Can't believe I missed that - I think I've been working far too many hours! Smilie
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