Shell Programming and Scripting

Hi ALL,

I am making a script that search all then worldwriteable dir in documentroot.I have manage to find all the dir now i want to match each file extension in worldwriteable against a list of array which contain file like php html etc,if i find any file then print dirname. Dont see to get any idea how i do that.i past my code for reiew and comments



#!/bin/bash

list[0]="php"
list[1]="html"
Docroot[0]="/var/www/html/"

export IFS=$'\n'

# Loop through our array.
for x in ${Docroot[@]}
do
# Find all directories & subdirectories
for i in $(find $x -type d -perm /o=w )
do



echo $i

done
done


This is a small output
/var/www/html/test3
/var/www/html/test3/abc
/var/www/html/test3/gallery
/var/www/html/test/abc

Hi now i can also print the file inside all dir,Plz help me with matching,Thnks

#!/bin/bash

list[0]="php"
list[1]="html"
Docroot[0]="/var/www/html/"

export IFS=$'\n'

# Loop through our array.
for x in ${Docroot[@]}
do
# Find all directories & subdirectories
for i in $(find $x -type d -perm /o=w )
do

for j in $(ls -l $i)
do


echo $j

done
done
done


Output

total 8
drwxrwxrwx 2 root root 4096 2008-09-19 18:44 abc
-rw-r--r-- 1 root root 0 2008-09-10 17:21 abc2.php
-rw-r--r-- 1 root root 0 2008-09-10 17:21 abc3.php
-rw-r--r-- 1 root root 0 2008-09-10 17:21 abc.php
drwxrwxrwx 2 root root 4096 2008-09-19 01:53 gallery
-rw-r--r-- 1 root root 0 2008-09-19 18:43 abc.php

what do u mean by matching, pls explain, match files from where to where.

what you want to match, give some example, so can be think on it and put suggestion on it.

Thanks,
Bash

Hi

I mean comparing,I have change the code now i can do comparing , i am facing a new problem ,One is that i m using concatenation to print the total dir out side the loop but its not working as i want my be i m missing the point,I will explain how i need below,Please see example,The number in example is count like if i find any file with php or html extension i incrses the count.Give a soulation to current code i left pervious becaus it was hard and difficult to manage.Thx


Code

find /var/www/html -type d -perm /o=w | while read DIR
do
test=$(find "$DIR" -type f \( -name "*.html" -o -name "*.php" \) -print )


$test2="$test2 $test"
done

print $test2


I want (Example)
/var/www/htm/test 3

Current Out put

/var/www/html/phpBB3/includes/utf/data/recode_cjk.php
/var/www/html/phpBB3/includes/utf/data/search_indexer_20.php
/var/www/html/phpBB3/includes/utf/data/search_indexer_95.php
/var/www/html/phpBB3/includes/utf/utf_tools.php

You're nearly there, you just need to count the number of lines from your find command:

Code:

find /var/www/html -type d -perm /o=w | while read DIR
do 
    echo $DIR $(find "$DIR" -type f \( -name "*.html" -o -name "*.php" \) -print | wc -l)
done

Thx its work but giving extra count look at output,It also giving count of the dir inside other dir.Look ls -l output,Any quic and dirty idea,and how can i do like this /var/www/abc 3 ??.Becz still caught in same problem to get one dir not dir + file name.
drwxrwxrwx 2 root root 4096 2008-09-19 18:44 abc
-rw-r--r-- 1 root root 0 2008-09-10 17:21 abc2.php
-rw-r--r-- 1 root root 0 2008-09-10 17:21 abc3.php
-rw-r--r-- 1 root root 0 2008-09-10 17:21 abc.php
drwxrwxrwx 2 root root 4096 2008-09-19 01:53 gallery

Code output.
/var/www/html/test3/abc.php
/var/www/html/test3/abc3.php
/var/www/html/test3/abc/abc.php
/var/www/html/test3/abc/abc2.php
/var/www/html/test3/abc2.php 5

What operating system are you using? As far as I know -perm /o=w is not valid syntax, but I presumed you have tested this? Try -perm -020 instead maybe.

Also I made an error in the above, if you run find again to count files it will count those in subdirectories - do you want that? If not, try:

Code:

find /var/www/html -type d -perm -020 | while read DIR
do 
    echo $DIR $(cd "$DIR"; ls *.html *.php 2>/dev/null | wc -l)
done