Shell Programming and Scripting

Hello,

I need help with finishing this script.

I just want to find users that are locked more than 30 days and also assiociate this script with another one that show users which have not logged in at all for each server that I have.

serverlist=/home/myusername/server.lst
for server in `cat $serverlist | awk '{print $1}'`
do
locked=`ssh $server lsuser ALL|awk '/account_locked=true/ {print $1}'`

echo $server >> locked.txt
echo $locked >> locked.txt
done

Well, I don't have any easy solution but I would do that with join command.

1] I would use files: ${server}_locked.txt - because of later usage of join command

2] ${server}_locked.txt file structure:

number_of_days_user_is_locked<a char that username cannot contain>user

3] if you run the script once a day you have old information about users of a given server and fresh ones. You join old file with the new one and you know to which user you have to update the number of days. Then you use the join command again and use the flag -a (prints unpairable lines) which gives you users which should have 0 as the number of locked days.

I know it's generally described but I hope it still helps a little.

Looking in usr/security/lastlog

I am looking at time_last_login = 1219247186.

Is there a way that I can use this to check on users that have been looked for 30days or more. With those user I will lock and anything older than 60 days I will delete.